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Alecsey [184]
3 years ago
13

500 mole of ammonia (nh3) occupies a 1.2 l flask at 150°c. calculate the pressure of the ammonia inside the flask.

Chemistry
1 answer:
kondaur [170]3 years ago
8 0
Given; 
no. of moles (n) = 500 moles
volume (V) = 1.2 l
temperature (T) = 150°C = (150 + 273 )k = 423 k
gas constant (R) = 0.0821 L- atm / mole-K

then,

PV = nRT
P × 1.2 = 500 × 0.0821 × 423
P =  14,470.125 atm

But I guess pressure is too high. Well this should be the way.
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Answer :  The formal charge on the C is, (-1) charge.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, CH_3^{-1}

As we know that carbon has '4' valence electrons and hydrogen has '1' valence electron.

Therefore, the total number of valence electrons in CH_3^{-1} = 4 + 3(1) + 1 = 8

According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.

Now we have to determine the formal charge on carbon atom.

Formula for formal charge :

\text{Formal charge}=\text{Valence electrons}-\text{Non-bonding electrons}-\frac{\text{Bonding electrons}}{2}

\text{Formal charge on C}=4-2-\frac{6}{2}=-1

The formal charge on the C is, (-1) charge.

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3 years ago
DIRECTIONS: Use the Word Bank to answer the questions below. For questions 2 and 3 circle the correct choice.
Angelina_Jolie [31]

Explanation:

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3. The shells closer to the nucleus are ​smaller​ and can hold ​less​ electrons.

4. The closest shell (closest to the nucleus) can hold a maximum of two electrons.

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7. Once the third shell contains Eighteen electrons, the fourth shell begins to fill.

8. The arrangement of electrons in shells around the nucleus is referred to as an atom's electronic configuration.

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Answer:

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Explanation:

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6 0
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Alex777 [14]

Answer:

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Explanation:

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In either case, the ease of departure of the leaving group is determined by the nature of the C-X bond. The stronger the C-X bond, the worse the leaving group will be in nucleophilic substitution. The order of strength of C-X bond is F>Cl>Br>I.

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Therefore, the ease of the use of halide ions as leaving groups follows the trend; Iodide> Bromide > chloride > flouride

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USPshnik [31]

Answer:

See explanation

Explanation:

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7 0
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