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3 years ago

9

My answer is B do you agree

2 answers:

insens350 [35]3 years ago

8 0

Answer:

Area is increased by 4 i have my question and i need you to answer plz thxxxx

Step-by-step explanation:

Nastasia [14]3 years ago

6 0

Answer:

The area increased by a factor of 4

Step-by-step explanation:

If the scale factor is 4 and only the height changes

A = 1/2 bh

A = 1/2 b(4h)

A = 1/2 bh(4)

A = A4

The new area is the old area increased by 4

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The cost price of a box and a pen is Rs 120. The box is sold at 10% profita the pen is sold at 10% loss. If the selling price of

matrenka [14]

Answer:

3.803% Profit

Step-by-step explanation:

First let us calculate total sales, then calculate the total cost, and then divide the two.

Sale: 120*1.1=132 and 52*.9=46.8

Cost: 120 and 52

Profit equation:

$\frac{Net sales-COGS}{Net Sales} =Profit$

$\frac{(132+46.8)-(120+52)}{(132+46.8)}$

Simplify:

$\frac{6.8}{178.8} =.03803$ or 3.803% Profit

5 0

3 years ago

HELP PLEASE! Will give out brainliest

charle [14.2K]

Answer:

i would say b but not sure

Step-by-step explanation:

hope this helps let me know if i got it wrong

4 0

3 years ago

Solve the system by substitution: <br> 3x + 2y = 26<br> Y=x + 3

Orlov [11]

Answer:

x = 4

Step-by-step explanation:

3x + 2y = 26

y = x + 3

Plug in the equation for y

3x + 2(x + 3) = 26

Multiply the 2 with what is in the parantheses

3x + 2x + 6 = 26

Combine like terms and solve for x

5x + 6 = 26

5x = 20

x = 4

5 0

3 years ago

Read 2 more answers

Please help im so confused lol

BARSIC [14]

Answer:

1. Percent

2. Number

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f

castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean $(\mu) = 115 \times 20$

= 2300

Standard deviation = $20 \times \sqrt{115}$

Standard deviation (SD) = 214.4761

TO find:

a) $P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{1200}{214.4761})$

$P(x > 3500)= P(Z >5.595)$

From the Z-table, since 5.595 is > 3.999

$P(x > 3500)=1-0.9999$

P(x > 3500) = 0.0001

b)

Here, the replacement time for the mean $(\mu) = \dfrac{0+0.5}{2}$

= 0.25

Replacement time for the Standard deviation $\sigma = \dfrac{0.5-0}{\sqrt{12}}$

$\sigma = 0.1443$

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = $\sqrt{(115\times 20^2) +(114\times (0.1443)^2)}$

= $\sqrt{(115\times 400) +(114\times 0.02082249}$

= $\sqrt{(46000) +2.37376386}$

= $\sqrt{(46000) +(2.37376386)}$

= $\sqrt{46002.374}$

= 214.482

Now; the required probability:

$P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})$

$P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})$

$P(x > 4125) = P(Z >8.376)$

$P(x > 4125) =1- P(Z$

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0

2 years ago