Answer:
.
Step-by-step explanation:
Answer:
Solution given:
AB=3units
<B=45°
<C=63°
DF=3units
<E=63°
<F=45°
for congruence opposite corresponding angle or side should be equal
so
∆ABCis congruent to ∆DFE by A.A.S axiom
Similarly
its another name also be
∆BAC=~ ∆FDE
you got it.third one.
Given:
The equation of ellipse is

To find:
The length of the minor axis.
Solution:
The standard form of an ellipse is
...(i)
where, (h,k) is center, if a>b, then 2a is length of major axis and 2b is length of minor axis.
We have,
...(ii)
On comparing (i) and (ii), we get

Taking square root on both sides.

Consider only positive value of b because length cannot be negative.

Now,
Length of minor axis = 
= 
= 
So, the length of minor axis is 8 units.
Therefore, the correct option is B.
Answer:
or y = 0.25x + 0.5
Step-by-step explanation:
You need to try change the subject from x to y.
x = 4y - 2
We first move -2 to the left, making the equation
x + 2 = 4y i.e.
4y = x + 2
We then divide both sides by 4.
or y = 0.25x + 0.5
We now have successfully made y the subject, and effectively solving the equation.