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fiasKO [112]
3 years ago
8

Write the correct abbreviation for each metric unit

Physics
1 answer:
Romashka-Z-Leto [24]3 years ago
5 0
Meter - m
Kilometer - km
Hectometer- hm
Dekameter - dam
Decimeter - dm
Centimeter - cm
Millimeter - mm
Micrometer - μm
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oksano4ka [1.4K]

Answer:

1D

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Fiesta28 [93]
The answer should be B - lasts longer.
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If two particles have equal kinetic energies, are their momenta necessarily equal? explain.
Mandarinka [93]

Answer:

No the given statement is not necessarily true.

Explanation:

We know that the kinetic energy of a particle of mass 'm' moving with velocity 'v' is given by

K.E=\frac{1}{2}mv^{2}

Similarly the momentum is given by m\times v

For 2 particles with masses m_{1},m_{2}and moving with velocities v_{1},v_{2} respectively the respective kinetic energies is given by

K.E_{1}=\frac{1}{2}m_{1}v_{1}^{2}

K.E_{2}=\frac{1}{2}m_{2}v_{2}^{2}

Similarly For 2 particles with masses m_{1},m_{2}and moving with velocities v_{1},v_{2} respectively the respective momenta are given by

p_{1}=m_{1}\times v_{1}

p_{2}=m_{2}\times v_{2}

Now since it is given that the two kinetic energies are equal thus we have

\frac{1}{2}m_{1}v_{1}^{2}=\frac{1}{2}m_{2}v_{2}^{2}\\\\(m_{1}v_{1})\times v_{1}=(m_{2}v_{2})\times v_{2}\\\\p_{1}\times v_{1}=p_{2}\times v_{2}\\\\\therefore \frac{p_{1}}{p_{2}}=\frac{v_{2}}{v_{1}}............(i)

Thus we infer that the moumenta are not equal since the ratio on right of 'i' is not 1 , and can be 1 only if the velocities of the 2 particles are equal which becomes a special case and not a general case.

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4 years ago
The distance a spring stretches varies directly as the amount of weight that is hanging on it. A weight of 2.5 pounds stretches
julsineya [31]
We use the equation y = kx
y = 18, x = 2.5

18 = k2.5
k = 7.2

x = 6.4
y = 7.2*6.4
y = 46.08

hope this help
5 0
3 years ago
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