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2 years ago

PLEASE ANSWER QUICKKK

Physics

1 answer:

valina [46]2 years ago

7 0

Answer:

Because the rope is stopping the force of gravity from acceleration it.

PLZ MARK BRAINLIEST :-)

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Acceleration is the rate of change of velocity. The velocity (positive means down) of a pumpkin thrown off the top of Cheadle ha

Rom4ik [11]

Explanation:

Below is an attachment containing the solution.

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2 years ago

How does the electrical force relate to the charge of an object?

mezya [45]

The electric force between two object is directly proportional to the net charge on each object and inversely proportional to the square of the distance between them. So, the answer is: The electrical force is directly proportional to the charge.

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2 years ago

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A ball rolls off the top of the roof of a building that is 13 meters tall. Calculate the amount of time it takes for it to hit t

kramer

Answer:

The ball takes $t=1 \cdot 917sec$ to hit the ground.

Explanation:

• The second equation of motion represents the total distances travelled by an object in a time interval of $\Delta t$ with an initial speed of $u$ and acceleration $a$ .

• To find the time, ball takes to hit the ground, use the formula: $s = ut + \frac{1}{2}a{t^2}$

Where, $t$ is time, $u$ is initial velocity, $a$ is acceleration and $s$ is displacement.

• In this case, $a = g = 9 \cdot 8m/se{c^2}$ .

• Placing the value of the given initial velocity, $u=0cm/s$ and displacement, $s = 13m$ in the above formula.

$& \therefore s = ut + \frac{1}{2}g{t^2} \\& \Rightarrow 13 = 0 \cdot t + \frac{1}{2} \times 9 \cdot 8 \times {t^2} \\$

$& \Rightarrow 13 = 4 \cdot 9{t^2} \\& \Rightarrow {t^2} = \frac{{13}}{{4.9}} \\& \Rightarrow t = 1 \cdot 917sec \\\end{align}\]$

• Hence, ball takes $t=1 \cdot 917sec$ to hit the ground.

Learn more about second equation of motion here:

brainly.com/question/19030143

5 0

2 years ago

Give the missing ammeter reading a and b. suggest why more current flow through some bulbs than through others Grade 10 question

pishuonlain [190]

Answer:

becaude of electricity

4 0

2 years ago

what is the initial velocity of a go-kart traveling at a uniform acceleration of 0.5 m/s^2 for 5s as it slows down to a stop?

timurjin [86]

The initial velocity of go-kart is 2.5 m/s.

Explanation:

Here, the uniform acceleration of go-kart is given as 0.5 m/s². Also the time required by it to stop is also given as 5 s. As acceleration is the measure of change in velocity per unit time.

In this case, the velocity should be changed from a value to zero to come to rest. So the initial velocity will be positive value and final velocity is zero.

As we know the values of acceleration, final velocity and time, the initial velocity can be easily determined as follows.

$Acceleration = \frac{Final velocity -Initial velocity}{Time}$

Since, final velocity is zero, acceleration is 0.5 m/s² and time is 5 s, then,

$-0.5=\frac{-\text {Initial velocity}}{5}$

Initial velocity = 0.5 × 5 = 2.5 m/s.

So the initial velocity of go-kart is 2.5 m/s.

8 0

2 years ago