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3 years ago

PLEASE ANSWER QUICKKK

Physics

1 answer:

valina [46]3 years ago

7 0

Answer:

Because the rope is stopping the force of gravity from acceleration it.

PLZ MARK BRAINLIEST :-)

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PLS HELP THIS IS WORTH A LOT OF POINTS ON MY TEST. WILL GIVE BRAINLIEST

Ede4ka [16]

Answer:

Explanation:

By conservation of energy, speed of the ball going up = speed of ball coming down with the ball stops at the top.

Because the gravity acceleration is constant, by symmetry, half of total time, 6/2 = 3s, is for going up and the last 3s for coming down.

Consider the last 3s when the ball drops from top to bottom, the initial velocity = 0 and acceleration = 10m/s^2

distance traveled = initial velocity * time + 1/2 * acceleration * time^2

= 0*3 + 1/2*10*3^2

= 5*9

= 45m

So maximum height of the ball is 45m.

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3 years ago

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The dimensions of a cylinder are changing, but the height is always equal to the diameter of the base of the cylinder. If the he

VashaNatasha [74]

Answer:

dV/dt = 9 cubic inches per second

Explanation:

Let the height of the cylinder is h

Diameter of cylinder = height of the cylinder = h

Radius of cylinder, r = h/2

dh/dt = 3 inches /s

Volume of cylinder is given by

$V = \pi r^{2}h$

put r = h/2 so,

$V = \pi \frac{h^{3}}{4}$

Differentiate both sides with respect to t.

$\frac{dV}{dt}=\frac{3h^{2}}{4}\times \frac{dh}{dt}$

Substitute the values, h = 2 inches, dh/dt = 3 inches / s

$\frac{dV}{dt}=\frac{3\times 2\times 2}{4}\times 3$

dV/dt = 9 cubic inches per second

Thus, the volume of cylinder increases by the rate of 9 cubic inches per second.

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3 years ago

Make a prediction based on your understanding of the cause-and-effect relationship between environment and trait: what happens w

Rom4ik [11]

Everything dies because it’s to extreme

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3 years ago

The radii of curvature of a biconvex lens are 4 cm and 15 cm. The lens is in air, its index of refraction is 1.5. An object is a

rewona [7]

Answer:

v = 6.315 cm

Explanation:

given,

R₁ = 4 cm = 0.04 m

R₂ = 15 cm = 0.15 m

n =1.5

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}=(n-1)(\dfrac{1}{R_1}-\dfrac{1}{R_2})$

$\dfrac{1}{v}-\dfrac{1}{-1}=(1.5-1)(\dfrac{1}{0.04}+\dfrac{1}{0.15})$

$\dfrac{1}{v}+1 = 0.5 \times 31.66$

$\dfrac{1}{v} = 15.833$

v = 0.06315 m

v = 6.315 cm

hence, the distance of the image from the back surface is v = 6.315 cm

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3 years ago

Which of the following is the most likely end for a star that is small to average in size? A. blue main sequence B. red supergia

likoan [24]

"White dwarf" is the one among the following choices given in the question that is <span>the most likely end for a star that is small to average in size. The correct option among all the options that are given in the question is the last option or option "D". I hope that this is the answer that has actually helped you.</span>

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3 years ago

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