The combined momentum of the passengers is 5000 kgm/s.
<h3>Combined momentum of the passenger</h3>
The combined momentum of the passengers is calculated as follows;
P = mv1 + mv2
where;
- m is mass of the passengers
- v1 is velocity of the first passenger
- v2 is velocity of the second passenger
P = m(v1 + v2)
P = 5000(-1 + 2)
P = 5000 kgm/s
Thus, the combined momentum of the passengers is 5000 kgm/s.
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Answer:
a) 3.65 seconds
b) 35.87 m/s
Explanation:
s = Displacement = 65.6 m
u = Initial velocity
v = Final velocity
t = Time taken
a = Acceleration due to gravity = 9.81 m/s² (downward direction is taken as positive and upward is taken as negative)
b) Equation of motion
Initial pop up velocity is 35.87 m/s
a)
It took 3.65 seconds to reach this height
Answer:
The answer is D. Balanced forces
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Answer:
4th answer
Explanation:
The gradient of a distance-time graph gives the speed.
gradient = distance / time = speed
Here, the gradient is a constant till 30s. So it has travelled at a constant speed. It means it had not accelarated till 30s. and has stopped moving at 30s.
Answer:
Explanation:
The formula for this, the easy one, is
where No is the initial amount of the element, t is the time in years, and H is the half life. Filling in:
and simplifying a bit:
and
N = 48.0(.0625) so
N = 3 mg left after 12.3 years
