The operating potential difference of a light bulb is 120 V. The power rating of the bulb is 70 W. (a) Find the current in the b
1 answer:
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Answer:
The answers can be found by considering the isothermal expansion equation as well as the ideal gas equation from where we have
The temperature T = 602.64K and the final pressure P = 110.24MPa
Explanation:
Numbeer of moles of gas = 3.00 mol
initial volume = 230.8×10−6 m3
final volume = 133.4×10−6 m3 .
released energy = 8240 J
Temperature = Constant = T
Pressure = =unknown
From the relation the combined ideal gas law, PV = nRT
Where R = 8.314 4621.JK−1mol−1
we have The release energy from compression P1V1 -P2V2
-qrev = -nRTln() = 8240J
n = 3
Hence -nRTln() = 3×8.314 462×ln
× T= -8240 J
or -13.67×T = -8240J, thus T = -8240/-13.67 = 602.64K
The Final pressure is given by
PV = n×R×T from where we have V = final volume thus
P = (n×R×T)/V = (3×8.134×602.64)÷(133.4×) = 110237041.1 N/
= 110.237MPa
Answer:
Options (3) and (6)
Explanation:
Janine drives 2.2 km East.
Since, distances measured in the East are positive,
Displacement = 2.2 km
Then she drives 4.4 km west
Displacement = -4.4 km
Followed by 1.7 km in the East
Displacement = 1.7 km
Total displacement = 2.2 - 4.4 + 1.7 = -0.5 km
km
Total distance covered by Janine = 2.2 + 4.4 + 1.7 = 8.3 km
d = 8.3 km
Therefore, Options (3) and (6) will be the answer.