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GREYUIT [131]
3 years ago
13

How many protons neutrons and electrons does zinc 66 have?

Chemistry
1 answer:
Liula [17]3 years ago
6 0
Zinc will always have 30 protons, so you'd have 66-30 = 36 neutrons

I hope it helped you!
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Weight of one mole of carbon = 12.01 g Weight of one mole of oxygen = 16.00 g The molecular weight (gram formula weight) for CO
murzikaleks [220]

Answer:

28.01g

Explanation:

Given the weight of one mole of Cabon as 12.01g and that of oxygen as 16.00g.

The molecular weight of a compound can be gotten by adding the molar weights of the elements that constitutes the compound .

The molecular weight of the compound CO is therefore

equal to the sum of the weight of both elements.

That’s = 12.01g + 16.00g

= 28.01g

Therefore, the molecular weight of CO is 28.01g

4 0
3 years ago
How are force, mass, and motion related?
Sonja [21]
Force causes all motion, and the larger the mass of an object the stronger the force needs to be to accelerate the object.
4 0
3 years ago
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What liquid is the most vicious ?
Dmitry [639]
Viscosity is basically how thick a liquid is so pancake syrup would be the answer
6 0
3 years ago
the reaction of aluminum with chlorine gas is shown 2Al + 3Cl2 -> 2AlCl3 based on this equation how many molecules of chlorin
Vanyuwa [196]

45 molecules of chlorine gas (Cl₂) are needed to react with 30 atoms of aluminum (Al)

The balanced equation for the reaction is given below:

2Al + 3Cl₂ —> 2AlCl₃

From the balanced equation above,

2 atoms of Al required 3 molecules of Cl₂.

With the above information, we can determine the number of molecules of Cl₂ needed to react with 30 atoms of Al. This can be obtained as follow:

From the balanced equation above,

2 atoms of Al required 3 molecules of Cl₂.

Therefore,

30 atoms of Al will require = \frac{30 * 3}{2}\\ = 45 molecules of Cl₂.

Thus, 45 molecules of chlorine gas (Cl₂) are needed to react with 30 atoms of aluminum (Al)

Learn more: brainly.com/question/24918379

3 0
2 years ago
If 65.5 moles of an ideal gas is at 9.15 atm at 50.30 °C, what is the volume of the gas?
qwelly [4]
To calculate for the volume, we need a relation to relate the number of moles (n), pressure (P), and temperature (T) with volume (V). For simplification, we assume the gas is an ideal gas. So, we use PV=nRT.

PV = nRT  where R is the universal gas constant
V = nRT / P
V = 65.5 ( 0.08205 ) (273.15 + 50.30) / 9.15 
V = 189.98 L
7 0
3 years ago
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