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lisov135 [29]
3 years ago
11

A student collected data about the distance a car travels over time.

Physics
2 answers:
Molodets [167]3 years ago
5 0

Answer:

Therefore the correct answer is B.  Scatterplot

Explanation:

This is an exercise in kinematics, in a measurement of distance against time, the process is described by the expression

          x = vo t + ½ a t2

where vo is the initial velocity. At the acceleration of the body, x the displacement and t the time.

Depending on the type of movement, a can be zero or different from zero.

In general, all these data are graphed in a DISPERSION graph where the distance is on the abscissa axis and the ordinate axis is time.

Therefore the correct answer is B

katovenus [111]3 years ago
4 0

Answer:

It's B. Scatterplot I just took the test

Explanation:

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A ball moving with an initial velocity of 5 m/s comes to rest after 2s. What was the ball's acceleration?
Inga [223]

Answer:

-2.5m/s²

Explanation:

The acceleration of a body is giving by the rate of change of the body's velocity. It is given by

a = Δv / t        ----------------(i)

Where;

a = acceleration (measured in m/s²)

Δv = change in velocity = final velocity - initial velocity   (measure in m/s)

t = time taken for the change (measured in seconds(s))

From the question;

i. initial velocity = 5m/s

final velocity = 0 [since the body (ball) comes to rest]

Δv = 0 - 5 = -5m/s

ii. time taken = t = 2s

<em>Substitute these values into equation (i) as follows;</em>

a = (-5m/s) / (2s)

a = -2.5m/s²

Therefore, the acceleration of the ball is -2.5m/s²

NB: The negative sign shows that the ball was actually decelerating.

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3 years ago
A 2000 kg roller coaster is at the top of a loop with a radius of 24 m. If its speed is 18 m/s at this point, what force does it
levacccp [35]

Answer:

46620\ \text{N}

Explanation:

m = Mass of roller coaster = 2000 kg

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v = Velocity of roller coaster = 18 m/s

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Normal force at the point will be

N-mg=\dfrac{mv^2}{r}\\\Rightarrow N=\dfrac{mv^2}{r}+mg\\\Rightarrow N=\dfrac{2000\times 18^2}{24}+2000\times 9.81\\\Rightarrow N=46620\ \text{N}

The force exerted on the track is 46620\ \text{N}.

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