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nalin [4]
3 years ago
10

Determine how potential and kinetic energy changes at each position of the pendulum as the ball swings from A to E. Position A:

Position B: Position C: Position D: Position E:
Physics
2 answers:
slavikrds [6]3 years ago
5 0
<h3><u>Answer;</u></h3>

Position A: Maximum potential  and minimum kinetic energy

Position B: losing potential and gaining kinetic  

Position C: Maximum kinetic  and minimum potential energy.

Position D: is losing kinetic and gaining potential  

Position E: Maximum potential and minimum kinetic energy.

<h3><u>Explanation;</u></h3>
  • Position A is a point of maximum potential energy and minimum kinetic energy since it is the highest point of the pendulum.
  • Position B, which is half way between A and C, the ball is losing potential energy and gaining kinetic energy. This occurs as the ball descends from the highest position to the lower position thus looses potential energy and gains kinetic energy.
  • Position C is the point of maximum kinetic energy and minimum potential energy. Because this is the lowest point of the pendulum and a point where the ball has maximum velocity.
  • At position D which is half way between C and E, the potential energy is increasing as the kinetic energy is decreasing. At this point the ball has half of its maximum potential energy.
  • At position E, he potential energy of the pendulum reaches its maximum value and is neither increasing nor decreasing at that point.
worty [1.4K]3 years ago
5 0

Answer: position A is all potential) position B) losing potential and gaining kinetic) position C) is all kinetic) position D) is losing kinetic and gaining potential) position E) is all potential.

Explanation: I just did the questions trust me these are right try them! good luck.

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(a) A light-rail commuter train accelerates at a rate of 1.35 m/s2 . How long does it take to reach its top speed of 80.0 km/h,
Mashcka [7]

Answer:

(a) Time t = 16.46 sec

(b) Time t =13.466 sec

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Explanation:

(a) As the train starts from rest its initial velocity u = 0 m/sec

Acceleration a=1.35m/sec^2

Final speed v = 80 km/hr

80km/hr=\frac{80\times 1000}{3600sec}=22.22m/sec

From first equation of motion v =u+at

So t=\frac{v-u}{a}=\frac{22.22-0}{1.35}=16.46 sec

(b) Now initial speed u = 22.22 m/sec

As finally train comes to rest so final speed v=0 m/sec

Deceleration a=1.65m/sec^2

So t=\frac{v-u}{a}=\frac{0-22.22}{-1.65}=13.466 sec

(c) We have given that initial velocity = 80 km/hr = 22.22 m/sec

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Time t = 8.30 sec

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3 years ago
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A pipe that is open at both ends has a fundamental frequency of 320 Hz when the speed of sound in air is 331 m/s.
fenix001 [56]

Question

What is the length of the pipe?

Answer:

(a) 0.52m

(b) f2=640 Hz and f3=960 Hz

(c) 352.9 Hz

Explanation:

For an open pipe,  the velocity is given by

v=\frac {2Lf}{n}

Making L the subject then

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(b)

The next two harmonics is given by

f2=2fi

f3=3fi

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f3=3*320=960 Hz

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(c)

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