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nalin [4]
4 years ago
10

Determine how potential and kinetic energy changes at each position of the pendulum as the ball swings from A to E. Position A:

Position B: Position C: Position D: Position E:
Physics
2 answers:
slavikrds [6]4 years ago
5 0
<h3><u>Answer;</u></h3>

Position A: Maximum potential  and minimum kinetic energy

Position B: losing potential and gaining kinetic  

Position C: Maximum kinetic  and minimum potential energy.

Position D: is losing kinetic and gaining potential  

Position E: Maximum potential and minimum kinetic energy.

<h3><u>Explanation;</u></h3>
  • Position A is a point of maximum potential energy and minimum kinetic energy since it is the highest point of the pendulum.
  • Position B, which is half way between A and C, the ball is losing potential energy and gaining kinetic energy. This occurs as the ball descends from the highest position to the lower position thus looses potential energy and gains kinetic energy.
  • Position C is the point of maximum kinetic energy and minimum potential energy. Because this is the lowest point of the pendulum and a point where the ball has maximum velocity.
  • At position D which is half way between C and E, the potential energy is increasing as the kinetic energy is decreasing. At this point the ball has half of its maximum potential energy.
  • At position E, he potential energy of the pendulum reaches its maximum value and is neither increasing nor decreasing at that point.
worty [1.4K]4 years ago
5 0

Answer: position A is all potential) position B) losing potential and gaining kinetic) position C) is all kinetic) position D) is losing kinetic and gaining potential) position E) is all potential.

Explanation: I just did the questions trust me these are right try them! good luck.

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Refer to the diagram shown below.

Neglect air resistance.
The horizontal component of the launch velocity is
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The vertical component of the launch velocity is
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The acceleration due to gravity is g =9.8 m/s².
The time, t s, for the ball to reach a height of 3 m is given by 
(12.036 m/s)*(t s) - (1/2)*(9.8 m/s²)*(t s)² = (3 m)
12.036t - 4.9t² - 3 = 0
2.4543t - t² - 0.6122 = 0
t² - 2.4563t + 0.6122 = 0
Solve with the quadratic formula.
t = (1/2)[2.4563 +/- √(6.0334 - 2.4488)]
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The ball reaches a height of 3 m twice.
The first time it reaches 3 m height is 0.2815 s.

Part a.
The vertical velocity when t = 0.2815 s is
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The velocity at a height of 3.0 m  is 18.5 m/s (nearest tenth)

Part b.
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Answer:

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a = (Vf - Vo) / t

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