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masha68 [24]
3 years ago
13

A cyclist travels 20km in 4hrs.What speed did the cyclist cycle at?​

Physics
2 answers:
Margaret [11]3 years ago
5 0
Distance =20km

Time =4hr

Hence,speed = 20 divide by 4
That is 5 km/hr
Tanya [424]3 years ago
3 0

Answer: 5 km/hr

Explanation:

speed= distance divided by time

20/4

= 5 km/hr

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The power of a lens is 4. 0 diopters and its diameter is 5. 0 cm. what is the focal length of this lens?
fenix001 [56]

The focal length of the lens is 25cm

given:

power,p=4 diopters

what is focal length?

Focal length is the distance between the point of convergence of your lens and the sensor or film recording the image.

what is diopter?

The unit of optical power of lens is called diopter.It is the optical power of the lens.

we know,

p=1/f

where,

p= power

f= focal length

f=1/p

f=1/4

=0.25m

=25cm

Thus,the focal length of the lens is 25cm

learn more about focal length from here: https/brainly.com/question/28203589

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8 0
2 years ago
Is the intensity of light directly or inversely proportional to the concentration according to Beer-lambert's law?
Ahat [919]

Answer:

directly proportional

Explanation:

The Beer-Lambert law states that the quantity of light absorbed by a substance dissolved in a fully transmitting solvent is directly proportional to the concentration of the substance and the path length of the light through the solution.

8 0
3 years ago
a conical pendulum is formed by attaching a 50g mass to a 1.2m string. The mass swings around the circle of radius 25cm (a) calc
kipiarov [429]
A. 0.5 miles an hour 
B. 0.2 miles an hour
4 0
3 years ago
The 4.0 -kg head of an ax is moving at 3 m/s when it strikes a log and penetrates 0.01m into the log. What is the average force
Elina [12.6K]

Answer:

the average force the blade exerts on the log is 1791.05 N.

Explanation:

Given;

mass of the ax head, m = 4 kg

speed of the ax, v = 3 m/s

depth traveled into the log, d = 0.01 m

The time to traveled through the depth;

s = (\frac{u+v}{2} )t\\\\0.01 =  (\frac{0+3}{2} )t\\\\0.01 = 1.5t\\\\t = \frac{0.01}{1.5} \\\\t = 0.0067 \ s

The average force the blade exerts on the log;

F = ma=\frac{mv}{t} = \frac{4 \times 3}{0.0067} = 1791.05 \ N \\\\

Therefore, the average force the blade exerts on the log is 1791.05 N.

5 0
3 years ago
A resistor with an unknown resistance is connected in parallel to a 13 Ω resistor. When both resistors are connected in parallel
larisa86 [58]

Answer:

R2 = 10.31Ω

Explanation:

For two resistors in parallel you have that the equivalent resistance is:

\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\\\\      (1)

R1 =  13 Ω

R2 = ?

The equivalent resistance of the circuit can also be calculated by using the Ohm's law:

I=\frac{V}{R_{eq}}\\\\R_{eq}=\frac{V}{I}            (2)

V: emf source voltage = 23 V

I: current = 4 A

You calculate the Req by using the equation (2):

R_{eq}=\frac{23V}{4A}=5.75\Omega

Now, you can calculate the unknown resistor R2 by using the equation (1):

\frac{1}{R_2}=\frac{1}{R_{eq}}-\frac{1}{R_1}\\\\R_2=\frac{R_{eq}R_1}{R_1-R_{eq}}\\\\R_2=\frac{(5.75\Omega)(13\Omega)}{13\Omega-5.75\Omega}=10.31\Omega

hence, the resistance of the unknown resistor is 10.31Ω

8 0
3 years ago
Read 2 more answers
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