A. Picking up sound waves is the stage of listening that most people refer to as hearing.
<h3>
What is hearing?</h3>
Hearing, or auditory perception, is the ability to perceive sounds through an organ, such as an ear, by detecting vibrations as periodic changes in the pressure of a surrounding medium.
During learning process, when someone picks up the sound waves directed to him/her, it is known as the act of hearing,
Thus, picking up sound waves is the stage of listening that most people refer to as hearing.
Learn more about hearing here: brainly.com/question/14185060
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Surface air pressure is a consequence of the weight of the air acting on its surface. For example, if you are standing on Mars, the pressure around you is what you call the surface air pressure. Thus, that surface air pressure must be 0.007 atm.
Explanation:
It is given that,
Input voltage, ![V_i=12\ V](https://tex.z-dn.net/?f=V_i%3D12%5C%20V)
Input current, ![I_i=4\ A](https://tex.z-dn.net/?f=I_i%3D4%5C%20A)
Output current, ![I_o=0.8\ A](https://tex.z-dn.net/?f=I_o%3D0.8%5C%20A)
Number of turns in the secondary side of transformer, ![N_s=1177](https://tex.z-dn.net/?f=N_s%3D1177)
We need to find the number of turns in the primary side of the transformer. The current to the number of turns in the input and output is given by :
![\dfrac{N_s}{N_p}=\dfrac{I_p}{I_s}](https://tex.z-dn.net/?f=%5Cdfrac%7BN_s%7D%7BN_p%7D%3D%5Cdfrac%7BI_p%7D%7BI_s%7D)
Substituting all the above values
So,
![N_p=\dfrac{N_sI_s}{I_p}\\\\N_p=\dfrac{1177\times 4}{0.8}\\\\N_p=5885](https://tex.z-dn.net/?f=N_p%3D%5Cdfrac%7BN_sI_s%7D%7BI_p%7D%5C%5C%5C%5CN_p%3D%5Cdfrac%7B1177%5Ctimes%204%7D%7B0.8%7D%5C%5C%5C%5CN_p%3D5885)
So, the number of turns in primary side of the transformer is 5885.
The orbiting velocity of the satellite is 4.2km/s.
To find the answer, we need to know about the orbital velocity of a satellite.
<h3>What's the expression of orbital velocity of a satellite?</h3>
- Mathematically, orbital velocity= √(GM/r)
- r = radius of the orbital, M = mass of earth
<h3>What's the orbital velocity of a satellite orbiting earth with a radius 3.57 times the earth radius?</h3>
- M= 5.98×10²⁴ kg, r= 3.57× 6.37×10³ km = 22.7×10⁶m
- Orbital velocity= √(6.67×10^(-11)×5.98×10²⁴/22.7×10⁶)
=4.2km/s
Thus, we can conclude that the orbiting velocity of the satellite is 4.2km/s.
Learn more about the orbital velocity here:
brainly.com/question/22247460
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Answer:
The answer would be 735J
Explanation:
PE=mgh
=(mass)(force of gravity)(height)
=(25kg)(9.8m/s^2)(3m)
=735J