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sweet [91]
3 years ago
12

Write down the principals of them lever in points .​

Physics
1 answer:
Juli2301 [7.4K]3 years ago
6 0

The major principal of leaver is

load × load distance = effort × effort distance

where,

effort dis= distance between effort and fulcrum

load distance = distance between load and fulcrum......

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Which of these experiments would make use of qualitative data
7nadin3 [17]
It has to due with numbers so I would say the last one!
5 0
3 years ago
Read 2 more answers
The terminal velocity of a person falling in air depends upon the weight and the area of the person facing the fluid. Find the t
AVprozaik [17]

Answer:

v=115 m/s

or

v=414 km/h

Explanation:

Given data

A_{area}=0.140m^{2}\\  p_{air}=1.21 kg/m^{3}\\  m_{mass}=80kg

To find

Terminal velocity (in meters per second and kilometers per hour)

Solution

At terminal speed the weight equal the drag force

mg=1/2*C*p_{air}*v^{2}*A_{area}\\   v=\sqrt{\frac{2*m*g}{C**p_{air}*A_{area}} }\\ Where C=0.7\\v=\sqrt{\frac{2*9.8*80}{1.21*0.14*0.7} }\\ v=115m/s

For speed in km/h(kilometers per hour)

To convert m/s to km/h you need to multiply the speed value by 3.6

v=(115*3.6)km/h\\v=414km/h

5 0
3 years ago
How do I solve this
lesantik [10]

multiply grav pull by mass of astro maybe with a calculator

7 0
4 years ago
If the given wave has a frequency of 100 Hz, what frequency will the sixth harmonic have?
alukav5142 [94]

Answer:

600Hz

Explanation:

In electrical systems of alternating current, the harmonics are, as in acoustics, frequencies multiples of the fundamental working frequency of the system and whose amplitude decreases as the multiple increases. For example, if we have systems fed by the 50 Hz network, harmonics of 100, 150, 200, etc. may appear.

In our case having a fundamental wave of 100Hz, I can have harmonics of 200,300,400, ..., 600Hz

4 0
3 years ago
Which statement is true about gravitational forces?
Readme [11.4K]
Hey there!

Your correct answer would be (<span>Every mass exerts a gravitational force on every other mass.) It really doesn't matter the size in mass what so ever, gravity is stronger than mass, mass in nothing compared to mass. Therefor, gravity exert's mass on any object with any size of mass.

Your correct answer would be . . . 

</span>\boxed{\boxed{Every \ mass \ exerts \ a \ gravitational \ force \ on \ every \ other \ mass}}
<span>
Hope this helps.
~Jurgen
</span>
6 0
3 years ago
Read 2 more answers
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