In a projectile, the horizontal acceleration is zero. The velocity remains constant at all times. However, the <u>vertical acceleration</u> is -9.81m/s^2.
Hope this helps!
Answer:
(a) 
(b) 
(c) 
(d) 
Solution:
As per the question:
Angular velocity, 
Time taken by the wheel to stop, t = 2.4 h = 
Distance from the axis, R = 38 cm = 0.38 m
Now,
(a) To calculate the constant angular velocity, suing Kinematic eqn for rotational motion:
= final angular velocity
= initial angular velocity
= angular acceleration
Now,
Now,
(b) The no. of revolutions is given by:
(c) Tangential component does not depend on instantaneous angular velocity but depends on radius and angular acceleration:
(d) The radial acceleration is given by:
Linear acceleration is given by:
Answer:
224236.76 W
Explanation:
Power: This can be defined as the rate of change of energy. The S.I unit of power is Watt(W).
From the question,
P = E/t ......................... Equation 1
Where P = power, E = Energy or work, t = time.
But,
E = Wt×d.................. Equation 2
Where Wt = Total weight of the passengers, d = distance.
Substitute equation 2 into equation 1
P = (Wt×d)/t.............. Equation 3
Given: Wt = 590×150 =88500 N, d = 244 m, t = 96.3 s.
Substitute into equation 3
P = (88500×244)/96.3
P = 224236.76 W
Answer:
405 m
Explanation:
Given:
v₀ = 0 m/s
a = 2.5 m/s²
v = 45 m/s
Find: Δx
v² = v₀² + 2aΔx
(45 m/s)² = (0 m/s)² + 2 (2.5 m/s²) Δx
Δx = 405 m
