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2 years ago

6

A car accelerates at a rate of 6m/s^2 for 4 seconds until it has traveled a total of 40m what was the initial velocity of the ca

r

1 answer:

s344n2d4d5 [400]2 years ago

7 0

Using the 2nd equation of motion;

= s = ut + ½at²

= 40 = u×2 + ½ × 6 × 2²

= 40 = 2u + 3 × 4

= 40 - 12 = 2u

= 28/2 = u

= 14 m/s = u

And its done! Simple isn't? :P

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How did settlers changed the great plains?

Paul [167]

They farmed it and got rid of most of the buffalo. They also caused the locust plague from turning up the eggs in the dirt when it was first plowed.

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3 years ago

In a hydraulic lift, if the pressure exerted on the liquid by one piston is increased by 100 N/m2 , how much additional weight c

shepuryov [24]

Answer:

The additional weight and mass needed for lifting the other piston slowly is 2500 N and 254.92 kg, respectively.

Explanation:

By means of the Pascal's Principle, the hydraulic lift can be modelled by the following two equations:

Hydraulic Lift - Before change

$P = \frac{F}{A}$

Hydraulic Lift - After change

$P + \Delta P = \frac{F + \Delta F}{A}$

Where:

$P$ - Hydrostatic pressure, measured in pascals.

$\Delta P$ - Change in hydrostatic pressure, measured in pascals.

$A$ - Cross sectional area of the hydraulic lift, measured in square meters.

$F$ - Hydrostatic force, measured in newtons.

$\Delta F$ - Change in hydrostatic force, measured in newtons.

The additional weight is obtained after some algebraic handling and the replacing of all inputs:

$\frac{F}{A} + \Delta P = \frac{F}{A} + \frac{\Delta F}{A}$

$\Delta P = \frac{\Delta F}{A}$

$\Delta F = A\cdot \Delta P$

Given that $\Delta P = 100\,Pa$ and $A = 25\,m^{2}$ , the additional weight is:

$\Delta F = (25\,m^{2})\cdot (100\,Pa)$

$\Delta F = 2500\,N$

The additional mass needed for the additional weight is:

$\Delta m = \frac{\Delta F}{g}$

Where:

$\Delta F$ - Additional weight, measured in newtons.

$\Delta m$ - Additional mass, measured in kilograms.

$g$ - Gravitational constant, measured in meters per square second.

If $\Delta F = 2500\,N$ and $g = 9.807\,\frac{m}{s^{2}}$ , then:

$\Delta m = \frac{2500\,N}{9.807\,\frac{m}{s^{2}} }$

$\Delta m = 254.92\,kg$

The additional weight and mass needed for lifting the other piston slowly is 2500 N and 254.92 kg, respectively.

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2 years ago

you stand on a straight desert road at night and observe a vehicle approaching. this vehicle is equipped with two small headligh

inysia [295]

Answer:

The distance that you marginally able to discern that there are two headlights rather than a single light source is 6.084 km

Explanation:

Given:

d = distance = 0.679 m

λ = wavelength of the light = 537 nm = 537x10⁻⁹m

dp = pupil diameter = 4.81 mm = 0.00481 m

Question: What distance, in kilometers, are you marginally able to discern that there are two headlights rather than a single light source, dx = ?

For the separation of the peak from the central maximum it is:

$sin\theta =\frac{\lambda }{d_{p} } =\frac{537x10^{-9} }{0.00481} =1.116x10^{-4}$

In this case, the two small sources of the headlights have the same angle as the images that form inside the eye

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3 years ago

Why are weathering, erosion and deposition a NECESSARY process in the rock cycle?

Zarrin [17]

Answer:

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Explanation:

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2 years ago

Read 2 more answers

What is the state of y when y = k/x, x is halved.

tangare [24]

Answer:

y becomes doubled.

Explanation:

If;

y = $\frac{k}{x}$

what is the state of y when x is halved;

the given expression is an inverse relationship. When y increases, x is supposed to decrease and vice versa.

if x is halved; x = $\frac{x}{2}$

$\frac{k}{\frac{x}{2} }$ = $\frac{2k}{x}$

Now compare :

$\frac{k}{x}$ : $\frac{2k}{x}$

we see that y becomes doubled

8 0

2 years ago