Answer:
Negative Radicals ---→
1).Flouride = F⁻
2). Chloride = Cl⁻
3) Bromide = Br⁻
4) Iodide = I⁻
5) Sulphate = SO₄²⁻
6) Oxide = O²⁻
7) Nitride = N³⁻
8) Sulphur = S²⁻
9) Carbide = C⁴⁻
10) Hydroxide = OH⁻
11) Nitrate = NO₃⁻
12) Carbonate = CO²⁻
13) Hydrogen Carbonate = HCO₃⁻
14) Sulphate = SO₄²⁻
15).Sulphite = SO₃³⁻
16) Nitrate = NO₃⁻
17)Nitrite = NO₂⁻
18) Hydrogen Sulphite = HSO₃⁻
19) Hydrogen Sulphate = HSO₄⁻
20) Chromate = CrO₄²⁻
There are lot of Radicals which cannot be easily written. Although some of the Important Radicals which are commonly used are mentioned above.
Hope it helps,
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I think the correct answer from the choices listed above is option A. It is the salt bridge that balances charges that may build up as reduction and oxidation occur in a voltaic cell. The salt bridge is to <span>maintain charge balance because the electrons are moving from one half cell to the other.</span>
Answer:
T2 = 547.2K
Explanation:
Given:
V1 = 135 ml. V2 = 250 ml
T1 = 295.5K. T2 = ?
Using Charles's law and solving for T2,
V1/T1 = V2/T2
T2 = (V2/V1)T1
= (250 ml/135 ml)(295.5K)
= 547.2K (or 273.2°C)
