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diamong [38]
3 years ago
10

Carbons from acetyl CoA are transferred to the citric acid cycle. Which is the first round of the citric acid cycle that could p

ossibly release a carbon atom originating from this acetyl CoA?
Chemistry
1 answer:
Zielflug [23.3K]3 years ago
7 0

Answer:

In the third step of the citric acid cycle, the oxidation of isocitrate takes place and one molecule of carbon dioxide is released.

Explanation:

In the first step of citric acid cycle, acetylCoA combines with a four-carbon molecule, oxaloacetate, forming a six-carbon molecule, citrate.

In the second step, the citrate in the presence of enzyme anicotase is converted into isocitrate.

<u>In the third step, the oxidation of isocitrate takes place and one molecule of carbon dioxide is released leaving behind one five-carbon molecule called as α-ketoglutarate. During this step, NAD⁺ is reduced to form NADH. </u>

<u>This is first round of the citric acid cycle that could possibly release a carbon atom originating from this acetyl CoA.</u>

On series of reaction, another carbon dioxide molecule also being relased and oxaloacetate is regenerated again.

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2) A balloon was inflated to a volume of 5.0 liters at a temperature of
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Answer:

6.12 L

Explanation:

Given that,

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Final temperature, T₂ = 147°C = 420 K

We need to find its new volume. The relation between volume and temperature is given by :

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{5\times 420}{343}\\\\V_2=6.12\ L

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8 0
2 years ago
A certain object has a volume of 25.0 ml and a mass of 100 g. what is the density of the object
Tpy6a [65]
Density= mass/volume

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8 0
3 years ago
Select the reagents you would use to synthesize the compounds below from benzene. Use the minimum number of steps. No more than
jekas [21]

Answer:

Explanation:

Using the necessary reagents to faciliate the synthesis of the organic compounds as shown in the attached file.

8 0
3 years ago
What mass of oxygen is needed to combust and produced 6.4 moles of carbon dioxide gas?
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6 0
3 years ago
Which compound has the same empirical and molecular formula ethyne ethene ethane methane?
Margaret [11]
Empirical formula is the simplest ratio of whole numbers of components in a compound 
molecular formula is the actual ratio of components in a compound .
the molecular formula for the compounds given are as follows
ethyne  - C₂H₂
ethene - C₂H₄
ethane - C₂H₆
methane - CH₄
the actual ratios of the elements                 simplified ratio
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ethyne            2:2                                             1:1
ethene            2:4                                             1:2
ethane            2:6                                             1:3
methane         1:4                                             1:4
the only compound where the actual ratio is equal to the simplified ratio is methane 
therefore in methane molecular formula CH₄ is the same as empirical formula CH₄
6 0
3 years ago
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