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diamong [38]
3 years ago
10

Carbons from acetyl CoA are transferred to the citric acid cycle. Which is the first round of the citric acid cycle that could p

ossibly release a carbon atom originating from this acetyl CoA?
Chemistry
1 answer:
Zielflug [23.3K]3 years ago
7 0

Answer:

In the third step of the citric acid cycle, the oxidation of isocitrate takes place and one molecule of carbon dioxide is released.

Explanation:

In the first step of citric acid cycle, acetylCoA combines with a four-carbon molecule, oxaloacetate, forming a six-carbon molecule, citrate.

In the second step, the citrate in the presence of enzyme anicotase is converted into isocitrate.

<u>In the third step, the oxidation of isocitrate takes place and one molecule of carbon dioxide is released leaving behind one five-carbon molecule called as α-ketoglutarate. During this step, NAD⁺ is reduced to form NADH. </u>

<u>This is first round of the citric acid cycle that could possibly release a carbon atom originating from this acetyl CoA.</u>

On series of reaction, another carbon dioxide molecule also being relased and oxaloacetate is regenerated again.

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Sublimation. Sublimation is the change of a solid direct to gas or vapour without becoming liquid

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Pablo's experiments confirm the relationship between pressure and the number of gas molecules. as the pressure in a system incre
horrorfan [7]
The correct answer is:  [C]:  
___________________________________________________________
          "<span>pressure and the number of gas molecules are directly related."
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<u>Note</u>:  The conclusion was: "</span> as the pressure in a system increases, the number of gas molecules increases" — over the course of many trials.
          This means that the "pressure" and the "number of gas molecules" are directly related.

Furthermore, this conclusion is consistent with the "ideal gas law" equation:

     " PV = nRT " ; 
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in which:

    "P = Pressure" ; 
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        All other factors held equal, when "n" (the "number of gas molecules") 
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6 0
3 years ago
Read 2 more answers
What chemical compound is crucial to marine life and how is it disappearing?
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Nitrogen is crucial to the marine life and it is disappearing because it cannot be assimilated by most organisms in the water.
5 0
3 years ago
Part A Which acid in each of the following pairs has the stronger conjugate base? Match the words in the left column to the appr
vichka [17]

Answer:

HF

H₂S

H₂CO₃

NH₄⁺

Explanation:

<em>Which acid in each of the following pairs has the stronger conjugate base?</em>

According to Bronsted-Lowry acid-base theory, <em>the weaker an acid, the stronger its conjugate acid</em>. Especially for weak acids, pKa gives information about the strength of such acid. <em>The higher the pKa, the weaker the acid.</em>

<em />

  • Of the acids HCl or HF, the one with the stronger conjugate base is HF because it is a weak acid.
  • Of the acids H₂S or HNO₂, the one with the stronger conjugate base is    H₂S  because it is a weaker acid. pKa (H₂S) = 7.04 > pKa (HNO₂) = 3.39
  • Of the acids H₂CO₃ or HClO₄, the one with the stronger conjugate base is H₂CO₃ because it is a weak acid.
  • Of the acids HF or NH₄⁺, the one with the stronger conjugate base is NH₄⁺ because it is a weaker acid. pKa (HF) = 3.17 < pKa (NH₄⁺) = 9.25
6 0
3 years ago
1. How much 6.0 M HNO3 is needed to neutralize 39 mL of 2.0 M KOH?
quester [9]

Answer:

For 2. the answer is 15.0 mL

For other examples, you can solve by exact way as I have solved the 2nd example.

I have writen down all the balanced chemical reaction equation for examples 1, 3, 4, 5 for you. ( picture 2 )

Explanation:

Please see the step-by-step solution in the picture attached below.(picture 1)

Hope this answer can help you. Have a nice day!

6 0
3 years ago
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