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Elza [17]
3 years ago
10

I don't understand any of these

Chemistry
1 answer:
77julia77 [94]3 years ago
3 0
Ok well whats the questions
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PV = nRT. If P = 1 atm, V = 5.0 liter, R = 0.0821 L.atm/mol.K, and T = 293 K; what is the value of n?
Leya [2.2K]

Answer:

n = 0.207 mole

Explanation:

We have,

P = 1 atm

V = 5 liter

R = 0.0821 L.atm/mol.K

T = 293 K

We need to find the value of n. The relation is as follows :

PV = nRT

Solving for n,

n=\dfrac{PV}{RT}\\\\n=\dfrac{1\times 5}{0.0821 \times 293}\\\\n=0.207\ \text{mol}

So, the value of n is 0.207 mol.

6 0
2 years ago
What are the answers for this question<br> Don't just answer for points
Kisachek [45]

Answer:

i cant see it very much i dont think no one can

Explanation:

5 0
3 years ago
Read 2 more answers
The table below shows the dimensions of two colored cubes.
Lynna [10]

Answer:

Red, because it has less volume and more amount of matter.

Explanation:

3 0
2 years ago
The equilibrium constant for the gas phase reaction N2 (g) + O2 (g) ⇌ 2NO (g) is Keq = 4.20 ⋅ 10-31 at 30 °C. At equilibrium, __
pychu [463]

Answer:

At equilibrium, reactants predominate.

Explanation:

For every reaction, the equilibrium constant is defined as the ratio between the concentration of products and reactants. Thus, for the reaction N2 (g) + O2 (g) ⇌ 2NO the expression of its equilibrium constant is:

Keq = \frac{[NO]^{2}}{[O_{2} ][N_{2}]}

Since the equilibrium constant is Keq = 4.20x10-31 the concentration of reactants O2 and N2 must be much higher than products to obtain such a small number as  4.20x10-31 at the equilibrium. Hence, at equilibrium reactants predominate.

5 0
3 years ago
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In a mixture of gases exerting a total pressure of 2.50 atm, carbon dioxide has a mole fraction of 0.450. What is the partial pr
AlladinOne [14]

Answer:

1.12 atm is the correct answer

3 0
3 years ago
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