Acceleration formulae is:
a=Fnet/mass
According to the question
a=7500N/1500kg
a=5m/s sq.
Find the average speed and the average velocity.
Average speed = distance / time
distance = 10 x 8000 m = 80,000 m
time = 20 min * 60 s/min = 1200 s
Average speed = 80,000 m / 1200 s = 66.67 m/s
Average velocity = displacement / time
Given that the race car made complete circles the final poin is the same initial point, then its displacement is zero and the average velocity is zero too.
PART A)
Here we know that
potential difference across the wire is

resistance of wire is

now by ohm's law



Part b)
Power rating is defined as rate of electrical energy
it is defined as

now we have


Answer:
A. Thickness and temperature
Explanation:
A useful formula that gives the free-fall distance from rest in 'T' seconds:
D = (1/2 G) x (T²)
G = 9.81 m/s²
1/2 G = 4.905 m/s²
D (5 seconds) = (4.905 m/s²) x (5 sec)²
= (4.905 m/s²) x (25 sec²)
= 122.625 meters .
Since the tower-top is 100m above ground,
the depth of the well, to the top of the water,
accounts for the additional 22.625 meters.
My question is: How do you know exactly when the stone hit the water ?
You probably stood at the top of the well and listened for the
sound of the 'plop'. But it took some time after the stone hit
the water for the sound of the plop to come back up to you.
Well, can't you just subtract that time ? Yes, but you need
to know how much time to subtract. That depends on the
depth of the well ... which is exactly what you're trying to
determine, so you don't know it yet.
Oh well. That's a deep subject.