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kotykmax [81]
2 years ago
13

A wave is produced in a rope. The wave has a speed of 33 m/s and a frequency of 22 Hz. What wavelength is produced? 0. 67 m 0. 7

5 m 1. 5 m 3. 0 m.
Physics
1 answer:
vekshin12 years ago
4 0

Answer:

Wavelength = <u>1.5 m</u>

Explanation:

The formula for waves in terms of wavelength, speed and frequency is:

Speed (v) = Frequency (f) × Wavelength (λ)

33 = 22 × λ

33 = 22λ

λ = \frac{33}{22}

So, λ = 1.5 m

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You are in a hot air balloon (yes, another balloon problem!) rising from the ground at a constant velocity of 2.00 m/s upward. t
Daniel [21]
If all you need is the initial speed of the cork, you can solve this using only two of your given:
2.00 m.s upward and 6.60 m.s horizontally.

If you take in consideration the movement of the cork, you know that it was both going up and forward at the same time, this means that it was moving at a diagonal direction. Now you can solve this by using the Pythagorean theorem where: 

c =  \sqrt{ a^{2} +  b^{2}  }

Why? Because the vertical and the horizontal motion creates a movement that is diagonal, which when put in a free-body diagram, creates a right triangle. 

Going back to your problem, when applying this, the diagonal of a right triangle is the hypotenuse, so this is what you are looking for. The horizontal and vertical motion will represent the other 2 sides of the triangle. 

Now let's put that into your formula:

c = \sqrt{ a^{2} + b^{2} }

Vi = \sqrt{ Vx^{2} + Vy^{2} }

Where: Vx is your horizontal velocity
             Vy is your vertical velocity
             Vi  is your initial velocity

Now let's put in your given:

Vi = \sqrt{ Vx^{2} + Vy^{2} }
Vi = \sqrt{ 6.60^2} + 2.00^{2} }
Vi = \sqrt{ 43.56 + 4.00 }
Vi = \sqrt{ 47.56 }
Vi = 6.8964 m/s

So your initial velocity is 6.8964 m/s or 6.90 m/s
5 0
3 years ago
Two sound waves (wave X and wave Y) are moving through a medium at the same speed. If wave X has a greater frequency than wave Y
Naya [18.7K]

Answer:

Wave X has a shorter wavelength.

Explanation:

It is given that, two sound waves (wave X and wave Y) are moving through a medium at the same speed.

Speed of a wave is given by :

v=\nu\times \lambda

Where,

\nu is frequency

\lambda is wavelength

The relation between the frequency and the wavelength is inverse. Wave X has greater frequency than Y, then wave X has a shorter wavelength.

Hence, the correct option is (B) "has a shorter wavelength".                     

8 0
3 years ago
A Carnot engine absorbs 1, 3 MJ of heat at 427 degree C and exhausts heat to a reservoir at 90 degree C. How much work does it d
Alex17521 [72]
<span>Carnot cycle efficiency = work done/heat supplied = (Th - Tc)/Th where, Th is temperature of hot reservoir and Tc is temperature of cold reservoir. we have given the values as Heat supplied = 1.3 MJ or 1300 KJ, Th = 427 degree C and Tc = 90 degree C. converting degree Celsius to kelvin temperatures, Th = 427 + 273 = 700 K Tc = 90 +273 = 363 solving equations, (700 - 363)/700 = work done / 1300 work done = 625.86 KJ i.e. 0.626 MJ work is done .</span>
5 0
3 years ago
(e)
Hatshy [7]

Answer:

≈933.3kg/m^3

Explanation:

Density=Mass/Volume

11200kg/12.0= 933.3333kg/m^3

5 0
3 years ago
A heat pump has a coefficient of performance that is 60% of the Carnot heat pump coefficient of performance. The heat pump is us
Nataliya [291]

Answer:

T_C=118.8 K= 154.2°C

Explanation:

COP_max of carnot heat pump= \frac{T_{H} }{T_{H}-T_{C} }

where T_H and T_C are temperatures of hot and cold reservoirs

Also COP=\frac{Q_H}{W}

in the question COP= \frac{60}{100} \times COP_{max}

⇒\frac{Q_H}{W} =\frac{60}{100}\times\frac{T_H}{T_H-T_C}

heat is added directly to be as efficient as via heat pump

Q_H= W

and T_H= 24° C= 297 K

1=\frac{60}{100}\times \frac{297}{297-T_C}

on calculating the above equation we get

T_C=118.8 K

the outdoor temperature for efficient addition of heat to interior of home

T_C=118.8 K= 154.2°C

6 0
3 years ago
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