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3 years ago

What is the importance of the IPK? What might happen if it did not exist?

Chemistry

1 answer:

Anna71 [15]3 years ago

8 0

Answer:

See detailed explanation.

Explanation:

Hello,

In this case, since the International Prototype of the Kilogram (IPK) is an object made of a platinum-iridium alloy that was used to define the magnitude of the mass of the kilogram as it weights 2.2 pounds or approximately 1 kg, yet it was replaced by a new definition of the kilogram based on physical constants. In such a way, it is important because it was the base for the current understanding of what a kilogram is and its relationship with other mass measurements.

Thus, if would not have existed, we were not be able to design and use balances or mass-measuring equipment in order to provide a reliable measure of the real mass of an object.

Best regards.

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A molecular orbital is a region of space in a covalent species where electrons are likely to be found. The combination of two at

lara [203]

Answer:

bonding molecular orbital is lower in energy

antibonding molecular orbital is higher in energy

Explanation:

Electrons in bonding molecular orbitals help to hold the positively charged nuclei together, and they are always lower in energy than the original atomic orbitals.

Electrons in antibonding molecular orbitals are primarily located outside the internuclear region, leading to increased repulsions between the positively charged nuclei. They are always higher in energy than the parent atomic orbitals.

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2 years ago

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Eva8 [605]

Answer:

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2 years ago

• We obtained the above 10.00-mL solution by diluting a stock solution using a 1.00-mL aliquot and placing it into a 25.00-mL vo

garik1379 [7]

Answer:

a) The relationship at equivalence is that 1 mole of phosphoric acid will need three moles of sodium hydroxide.

b) 0.0035 mole

c) 0.166 M

Explanation:

Phosphoric acid is tripotic because it has 3 acidic hydrogen atom surrounding it.

The equation of the reaction is expressed as:

$H_3PO_4 \ + \ 3NaOH -----> Na_3 PO_4 \ + \ 3H_2O$

1 mole 3 mole

The relationship at equivalence is that 1 mole of phosphoric acid will need three moles of sodium hydroxide.

b) if 10.00 mL of a phosphoric acid solution required the addition of 17.50 mL of a 0.200 M NaOH(aq) to reach the endpoint; Then the molarity of the solution is calculated as follows

$H_3PO_4 \ + \ 3NaOH -----> Na_3 PO_4 \ + \ 3H_2O$

10 ml 17.50 ml

(x) M 0.200 M

Molarity = $\frac{0.2*17.5}{1000}$

= 0.0035 mole

c) What was the molar concentration of phosphoric acid in the original stock solution?

By stoichiometry, converting moles of NaOH to H₃PO₄; we have

= $0.0035 \ mole \ of NaOH* \frac{1 mole of H_3PO_4}{3 \ mole \ of \ NaOH}$

= 0.00166 mole of H₃PO₄

Using the molarity equation to determine the molar concentration of phosphoric acid in the original stock solution; we have:

Molar Concentration = $\frac{mole \ \ of \ soulte }{ Volume \ of \ solution }$

Molar Concentration = $\frac{0.00166 \ mole \ of \ H_3PO_4 }{10}*1000$

Molar Concentration = 0.166 M

∴ the molar concentration of phosphoric acid in the original stock solution = 0.166 M

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3 years ago

How many significant digits are in 89015

Lilit [14]

Answer:

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Explanation:

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3 years ago

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sdas [7]

Explanation:

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2 years ago