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3 years ago

Select all of the true statements regarding chemical equilibrium.

Chemistry

2 answers:

8_murik_8 [283]3 years ago

5 0

Answer: OPTIONS B, C and D

Explanation:

At equilibrium, concentration of reactant and product are not necessarily equal to each other.

But concentration of both reactants and products is constant equal rates of forward reaction and backward reaction.

And at equilibrium, Interconversion of products and reactants occurs.

Hence Among the given B, C and D are correct.

aivan3 [116]3 years ago

3 0

Answer: The correct answer is d. The rates of the forward and reverse reactions are equal.

Explanation:

During a reversible reaction, a reaction that can occur to both sides of the equation, the chemical equilibirum is a state when the rates of reaction forward and reverse are equal, this means that the reaction never stops, it keep happening, but the conversion and decomposition rates are the same, and not necessarily the concentrations of reactants and products are equal.

Therefore, the correct answer is d. The rates of the forward and reverse reactions are equal.

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(a) Calculate the energy released by the alpha decay of 222 86Rn.

Alinara [238K]

Answer:

a). The energy released by the alpha decay of 222 Rn is to 218 Po :

= 5.596 MeV

b).The energy of the alpha particle is 5.5 MeV

c) The recoil energy of Po = 0.096 MeV

Explanation:

The equation for the alpha decay of Rn to Polonium is:

$_{86}^{222}\textrm{Rn}\rightarrow$ $_{2}^{4}\textrm{He}+_{84}^{218}\textrm{Po}$

The energy of the decay process can be calculated using:

$\Delta E=\Delta mc^{2}$

$\Delta m$ = Change in the mass

Mass of Po = 218.008965 u

Mass of He = 4.002603 u

Mass of Rn = 222.017576 u

$\Delta m$ = mass of Po + mass of He - mass of Rn

= 4.002603 + 218.008965-222.017576

= - 0.006008

$\Delta E=m(931.5MeV)$

$\Delta E=-0.006008\times 931.5MeV$

= -5.596 MeV

The negative sign means energy is released during the process.

b) The energy of the alpha particle is :

$\frac{Po\ mass }{Rn\ mass}\times E$

$\frac{218.0089}{222.0175}\times \Delta E$

$\frac{218.0089}{222.0175}\times 5.596$

= 5.494 MeV

= 5.5 MeV

c).

Recoil energy: When the parent nucleus is at rest before the decay then , there must be the some recoil of daughter nucleus to conserve the momentum.This is termed as recoil energy.

The energy of the recoil polonium atom :

The formula for recoil energy is :

The total energy - the kinetic energy

= 5.596 - 5.5

= 0.096 MeV

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Explanation:

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