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3 years ago

5

A blacksmith making a tool heats 525 grams of steel to 1230°C. After hammering the steel, she places it into a bucket of water t

o cool it. When
she removes the steel from the water, it's at 50°C. How much heat does the steel release if its specific heat capacity is 0.486 Joules/gram degree
Celslus?
A. 301,000 Joules
B. 12,800 Joules
C. 1,270 joules
D. 241 Joules
E. 4.62 joules

1 answer:

Simora [160]3 years ago

6 0

C
WELL HOPE THIS CAN HELP U

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In the natural world, limiting factors like the availability of food, water, shelter and space can change animal and plant populations. Other limiting factors, like competition for resources, predation and disease can also impact populations. Other changes in limiting factors will cause a population to decrease.

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2 years ago

If you have 6.25g of O2, how many moles of H2O are produced?

denis23 [38]

Answer:

0.4 moles of water produced by 6.25 g of oxygen.

Explanation:

Given data:

Mass of oxygen = 6.25 g

Moles of water produced = ?

Solution:

Chemical equation;

2H₂ + O₂ → 2H₂O

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 6.35 g/ 32 g/mol

Number of moles = 0.2 mol

Now we will compare the moles of oxygen with water:

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8 0

3 years ago

Omg GUYS I NEED HELPPP

Ilia_Sergeevich [38]

27) Partial pressure of oxygen: 57.8 kPa

29) Final volume: 80 mL

30) Final volume: 8987 L

31) Due to property of water of being polar, ice floats on water

Explanation:

27)

In a mixture of gases, the total pressure of the mixture is the sum of the partial pressures:

$p_T = p_1 + p_2 + ... + p_N$

In this problem, the mixture contains 3 gases (helium, carbon dioxide and oxygen). We know that the total pressure is

$p_T=201.4 kPa$

We also know the partial pressures of helium and carbon dioxide:

$P_{He}=125.4 kPa\\P_{CO_2}=18.2 kPa$

The total pressure can be written as

$p_T=p_{He}+p_{CO_2}+p_{O_2}$

where $p_{O_2}$ is the partial pressure of oxygen. Therefore, we find

$p_{O_2}=p_T-p_{He}-p_{CO_2}=201.4-125.4-18.2=57.8 kPa$

29)

Assuming that the pressure of the gas is constant, we can apply Charle's law, which states that:

"For an ideal gas at constant pressure, the volume of the gas is proportional to its absolute temperature"

Mathematically,

$\frac{V}{T}=const.$

where

V is the volume of the gas

T is the Kelvin temperature

We can re-write it as

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Here we have:

$V_1 = 42 mL$ (initial volume)

$T_1=-89^{\circ}C+273=184 K$ is the initial temperature

$T_2=77^{\circ}C+273=350 K$ is the final temperature

Solving for V2, we find the final volume:

$V_2=\frac{V_1 T_2}{T_1}=\frac{(42)(350)}{184}=80 mL$

30)

For this problem, we can use the equation of state for ideal gases, which can be written as

$\frac{p_1 V_1}{T_1}=\frac{p_2 V_2}{T_2}$

where in this problem:

$p_1 = 102.3 kPa$ is the initial pressure

$V_1=1975 L$ is the initial volume

$T_1=25^{\circ}C+273=298 K$ is the initial temperature

$p_2=21.5 kPa$ is the final pressure

$T_2=12^{\circ}C+273=285 K$ is the final temperature

And solving for V2, we find the final volume of the balloon:

$V_2=\frac{p_1 V_1 T_2}{p_2 T_1}=\frac{(102.3)(1975)(285)}{(21.5)(298)}=8987 L$

31)

A molecule of water consists of two atoms hydrogen bond with an atom of oxygen ( $H_2 O$ ) in a covalent bond.

While the molecul of water is overall neutral, due to the higher electronegativity of the oxygen atom, electrons are slightly shifted towards the oxygen atom; as a result, there is a slightly positive charge on the hydrogen side, and a slightly negative charge on the oxygen side (so, the molecules is said to be polar).

As a consequence, molecules of water attract each other, forming the so-called "hydrogen bonds".

One direct consequence of the polarity of water is that ice floats on liquid water.

Normally, for every substance on Earth, the solid state is more dense than the liquid state. However, this is not true for water, because ice is less dense than liquid water.

This is due to the polarity of water. In fact, when the temperature of water is decreased to freezing point and water becomes ice, the hydrogen bondings "force" the molecules to arrange in a lattice structure, so that the molecules become more spaced when they turn into solid state. As a result, ice occupies more volume than water, and therefore it is less dense, being able to float on water.

Learn more about ideal gases:

brainly.com/question/9321544

brainly.com/question/7316997

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#LearnwithBrainly

4 0

3 years ago

If 1,079.75 Joules of heat are added to 77.75 grams of water, by how many degrees Celsius would the water increase? Assume water

djyliett [7]

Answer:

If 1,079.75 Joules of heat are added to 77.75 grams of water, by 3.32 degrees Celsius the temperature of water will increase

$\Delta T=3.32 C^{0}$

Explanation:

$q = mC\Delta T$

Here , q = heat added / removed from the substance

m = mass of the substance taken

$\Delta T$ = Change in temperature

C = specific heat capacity of the substance

In liquid state the value of C for water is :

$4.18 J/gC^{0}$

Given values :

q = 1079.75 J

m = 77.75 gram

Insert the value of C, m , q in the given equation

$q = mC\Delta T$

on transposing ,

$\Delta T=\frac{q}{mC}$

$\Delta T=\frac{1079.75}{77.75\times 4.18}$

$\Delta T=3.32 C^{0}$

3 0

3 years ago