Answer :
and
are reactants.
and
are products.
Explanation :
Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.
In the balanced chemical reaction, the reactants and products are separated by right arrow.
The species present on the left side of the right arrow is the reactant and the species present on the right side of the right arrow is the product.
When ethanol react with oxygen gas then it gives carbon dioxide and water as a product.
The balanced chemical reaction will be:
![C_2H_5OH+3O_2\rightarrow 2CO_2+3H_2O](https://tex.z-dn.net/?f=C_2H_5OH%2B3O_2%5Crightarrow%202CO_2%2B3H_2O)
In the given balanced reaction,
and
are reactants.
and
are products.
Answer:
the answer would be 6.720
Simply subtract the combined mass by the mass of the beaker.
The answer has 3 decimal places because the least amount of decimal places in the equation is 3.
Option D for sure as it includes the phrase calorie which is a measure of energy.
In Thompson's model, an atom is made of protons and electrons. Protons carry simplest positive charge, while electrons carry simplest negative charge thus being the simplest negative particle in an atom.
Answer : The freezing point of the solution is, 260.503 K
Solution : Given,
Mass of methanol (solute) = 215 g
Mass of water (solvent) = 1000 g = 1 kg (1 kg = 1000 g)
Freezing depression constant = ![1.86^oC/m=1.86Kkg/mole](https://tex.z-dn.net/?f=1.86%5EoC%2Fm%3D1.86Kkg%2Fmole)
Formula used :
![\Delta T_f=K_f\times m\\T^o_f-T_f=K_f\times \frac{w_{solute}}{M_{solute}\times w_{solvent}}](https://tex.z-dn.net/?f=%5CDelta%20T_f%3DK_f%5Ctimes%20m%5C%5CT%5Eo_f-T_f%3DK_f%5Ctimes%20%5Cfrac%7Bw_%7Bsolute%7D%7D%7BM_%7Bsolute%7D%5Ctimes%20w_%7Bsolvent%7D%7D)
where,
= freezing point of water = ![100^oC=273K](https://tex.z-dn.net/?f=100%5EoC%3D273K)
= freezing point of solution
= freezing point constant
= mass of solute
= mass of solvent
= molar mass of solute
Now put all the given values in the above formula, we get
![273K-T_f=(1.86Kkg/mole)\times \frac{215g}{(32g/mole)\times (1kg)}](https://tex.z-dn.net/?f=273K-T_f%3D%281.86Kkg%2Fmole%29%5Ctimes%20%5Cfrac%7B215g%7D%7B%2832g%2Fmole%29%5Ctimes%20%281kg%29%7D)
By rearranging the terms, we get the freezing point of solution.
![T_f=260.503K](https://tex.z-dn.net/?f=T_f%3D260.503K)
Therefore, the freezing point of the solution is, 260.503 K