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Nezavi [6.7K]
3 years ago
5

A blacksmith making a tool heats 525 grams of steel to 1230°C. After hammering the steel, she places it into a bucket of water t

o cool it. When
she removes the steel from the water, it's at 50°C. How much heat does the steel release if its specific heat capacity is 0.486 Joules/gram degree
Celslus?
A. 301,000 Joules
B. 12,800 Joules
C. 1,270 joules
D. 241 Joules
E. 4.62 joules
Chemistry
1 answer:
Simora [160]3 years ago
6 0
C
WELL HOPE THIS CAN HELP U
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Describe the composition of humus and why it is an effective organic fertilizer.
asambeis [7]

Answer:

Humus, which ranges in colour from brown to black, consists of about 60 percent carbon, 6 percent nitrogen, and smaller amounts of phosphorus and sulfur. As humus decomposes, its components are changed into forms usable by plants.

samira-

5 0
2 years ago
A 35.40 gram hydrate of sodium carbonate, Na2CO3•nH2O, is heated to a constant mass. Its final weight is 30.2 g. What is formula
Sever21 [200]

Answer:

Na₂CO₃•H₂O

Explanation:

After it is heated, the remaining mass is the mass of sodium carbonate.

30.2 g Na₂CO₃

Mass is conserved, so the difference is the mass of the water:

35.4 g − 30.2 g = 5.2 g H₂O

Convert masses to moles:

30.2 g Na₂CO₃ × (1 mol Na₂CO₃ / 106 g Na₂CO₃) = 0.285 mol Na₂CO₃

5.2 g H₂O × (1 mol H₂O / 18.0 g H₂O) = 0.289 mol H₂O

Normalize by dividing by the smallest:

0.285 / 0.285 = 1.00 mol Na₂CO₃

0.289 / 0.285 = 1.01 mol H₂O

The ratio is approximately 1:1.  So the formula of the hydrate is Na₂CO₃•H₂O.

3 0
3 years ago
Read 2 more answers
Which of the following elements is the most reactive?    A. Arsenic (As)    B. Sulfur (S)    C. Fluorine (F)    D. Carbon (C
adell [148]
I think its a but i could be wrong

4 0
3 years ago
Read 2 more answers
How much ice (in grams) would have to melt to lower the temperature of 353 mL of water from 26 ∘C to 6 ∘C? (Assume the density o
Rashid [163]

Answer:

The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg

Explanation:

Heat gain by ice = Heat lost by water

Thus,  

Heat of fusion + m_{ice}\times C_{ice}\times (T_f-T_i)=-m_{water}\times C_{water}\times (T_f-T_i)

Where, negative sign signifies heat loss

Or,  

Heat of fusion + m_{ice}\times C_{ice}\times (T_f-T_i)=m_{water}\times C_{water}\times (T_i-T_f)

Heat of fusion = 334 J/g

Heat of fusion of ice with mass x = 334x J/g

For ice:

Mass = x g

Initial temperature = 0 °C

Final temperature = 6 °C

Specific heat of ice = 1.996 J/g°C

For water:

Volume = 353 mL

Density (\rho)=\frac{Mass(m)}{Volume(V)}

Density of water = 1.0 g/mL

So, mass of water = 353 g

Initial temperature = 26 °C

Final temperature = 6 °C

Specific heat of water = 4.186 J/g°C

So,  

334x+x\times 1.996\times (6-0)=353\times 4.186\times (26-6)

334x+x\times 11.976=29553.16

345.976x = 29553.16

x = 85.4197 kg

Thus,  

<u>The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg</u>

7 0
3 years ago
Why is it not recommended to use red, yellow or blue in the chromatography lab? Explain your reasoning in at least two sentences
bazaltina [42]

Answer:

solvent (such as water, oil or isopropyl alcohol) is allowed to absorb up the paper strip. ... Different molecules run up the paper at different rates. As a result, components of the solution separate and, in this case, become visible as strips of color on the chromatography paper.

Explanation:

Hope this helps leave a heart c:

3 0
3 years ago
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