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Likurg_2 [28]
3 years ago
12

where can quartzite be found? (needed for a school powerpoint, if you can link me any helpful websites that would be help so muc

h!)
Chemistry
2 answers:
Anna007 [38]3 years ago
3 0

Answer: "In the United States, you can find quartzite in eastern South Dakota, southwestern Minnesota, the Wasatch Range of Utah, the Baraboo Range of Wisconsin, Central Texas, near Washington, D.C., portions of Pennsylvania, and the mountains of Arizona and California. The town of Quartzite in Arizona takes its name from the rock in the nearby mountains."

Explanation:  .thoughtco.comquartzite-rock-geology-and-uses-4588608 <- Link with answer and more information on quartzite. May not be able to copy and paste because Brainly doesn't let me use a link.

nignag [31]3 years ago
3 0

Answer:

Explanation:

huh

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Determine the total pressure of all gases (at STP) formed when 50.0 mL of TNT (C3H5(NO3)3, , molar mass = 227.10 g/mol) reacts a
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Answer:

Total pressure is 1189 atm

Explanation:

This is the reaction:

4C₃H₅(NO₃)₃  →  6N₂  +  O₂  +  12CO₂  +  10H₂O

As we have the volume of TNT, we must know the density to find out the mass and then, apply molar mass to calculate mole.

TNT density = 1.654 g/mL

Density = mass / volume

1.654 g/mL = TNT mass / 50mL

1.654 g/mL . 50mL = TNT mass → 82.7 g

Mass / Molar mass = Mol → 82.7 g / 227.1 g/m = 0.364 mole

Now, we can calculate all the mole for the formed gases.

4 mole of TNT produce 6 mole N₂ ___ 1 mol O₂ __ 12 mole dioxide __ 10 mole of water

0.364 mole of TNT will produce:

- (0.364  . 6) /4 = 0.546 mole of produced nitrogen

- (0.364 . 1) /4 =  0.091 mole of produced oxygen

- (0.364 . 12) /4 = 1.092 mole of produced dioxide

- (0.364 . 10) /4 = 0.91 mole of produced vapour of water.

Total mole = 0.564 + 0.091 + 1.092 + 0.91 = 2.657 mole

Let's apply the Ideal Gases Law to find the total pressure, at STP

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But we have a volume of 50mL, and we have 2.657 total mole

Don't forget to convert 50 mL to L, cause the units for R

50 mL = 0.050L

P . 0.050L = 2.657 mol . 0.082L.atm/mol.K . 273K

P = (2.657 mol . 0.082L.atm/mol.K . 273K) / 0.050L

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