The freezing point depression of water is 1.86°C/m.kg
<span>K2S dissociates: </span>
<span>K2S ↔ 2K+ + S 2- </span>
<span>1mol K2S will produce 3 mol of ions. </span>
<span>Therefore in the freezing point equation: i = 3 </span>
<span>Depression of freezing point = Kf * i* m </span>
<span>Depression of freezing point = 1.86*3*0.195 </span>
<span>Depression of freezing point = 1.088°C </span>
<span>The solution will freeze at - 1.088°C </span>
1. Curiosity
2.<span> Necessity</span>
Explanation:
The given data is as follows.
n = 2 mol, P = 1 atm, T = 300 K
Q = +34166 J, W= -1216 J (work done against surrounding)
=
Relation between internal energy, work and heat is as follows.
Change in internal energy (
) = Q + W
= [34166 + (-1216)] J
= 32950 J
Also, 
=
32950 J = 

1321.06 K + 300 K =
= 1621.06 K
Thus, we can conclude that the final temperature of the gas is 1621.06 K.
Answer: The density, mass, and weight of the iron block make it difficult to lift than a cork block.
Explanation:
Correct Answer: option 1 i.e. C
Reason:
The the compound of interest i.e. XCl4, since there are 4 Cl atoms bonded to X. This signifies that the valency of X is 4.
There atomic number of C is 6. It's electronic configuration is giving by 1s2 2s2 2p2. Thus, there are 4 electrons in valence shell of C. This signifies that valency of C is 4. Hence the compound present in present case is CCl4.