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Alexus [3.1K]
3 years ago
13

Fission reactions can get out of control without what taking place?Select one of the options below as your answer:A. chain react

ion B. critical mass C. neutron heating D. neutron moderation E. subcritical mass
Chemistry
2 answers:
MariettaO [177]3 years ago
8 0

Answer: Option (A) is the correct answer.

Explanation:

Nuclear chain reactions occur in fission reactions only. Nuclear fission reactions are defined as the reactions in which larger nuclide splits into two or more smaller daughter nuclides.

For example, ^{235}_{92}U + ^{1}_{0}n \rightarrow ^{90}_{36}Kr + ^{144}_{56}Ba + 3^{1}_{0}n

These neutrons released will again bombard with the uranium atom leading to another fission reaction and this chain continues. And, if this chain gets disturbed by any external source then reaction becomes out of control as very high amount of energy releases in nuclear reactions.

Hence, in nuclear chain reactions the neutrons which are released in the previous fission reaction act as the starting material in the next reaction. Thus, this process continues to many reactions and hence, is known as nuclear chain reaction.

Thus, we can conclude that fission reactions can get out of control without chain reaction taking place.

guajiro [1.7K]3 years ago
3 0
Fission reactions can get out of control without neutron moderation. The correct option among all the options that are given in the question is the fourth option or option "D". The other options in this question can be discarded. I hope that this is the answer that you were looking for and it has come to your help.
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Julli [10]

Question 5 is the second one.


8 0
3 years ago
The solubility of o2 at 20c is 1.38 x10^-3. the partial presure of o2 in the air at sea level is 0.27 atm. using henery;s law, c
netineya [11]

<u>Answer:</u> The solubility of oxygen at 682 torr is 4.58\times 10^{-3}M

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{A}=K_H\times p_{A}

Or,

\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}

where,

C_1\text{ and }p_1 are the initial concentration and partial pressure of oxygen gas

C_2\text{ and }p_2 are the final concentration and partial pressure of oxygen gas

We are given:

Conversion factor used:  1 atm = 760 torr

C_1=1.38\times 10^{-3}M\\p_1=0.27atm\\C_2=?\\p_2=682torr=0.897atm

Putting values in above equation, we get:

\frac{1.38\times 10^{-3}}{C_2}=\frac{0.27atm}{0.897atm}\\\\C_2=\frac{1.38\times 10^{-3}\times 0.897atm}{0.27atm}=4.58\times 10^{-3}M

Hence, the solubility of oxygen gas at 628 torr is 4.58\times 10^{-3}M

4 0
3 years ago
Which of the following statements is true about catalysts? and Why?
LUCKY_DIMON [66]
I believe the correct answer from the choices listed above is option D. Catalysts lower the activation energy of a chemical reaction. It <span>is a substance which speeds up a reaction, but is chemically unchanged at the end of the reaction. It provides another pathway for the reaction to occur.</span>
8 0
4 years ago
Read 2 more answers
What is the voltage of a galvanic cell made with zinc (zn) and aluminum (al)?
bonufazy [111]
From the reduction standard potentials;
The emf of Zinc = -0.76 V
and the emf of Aluminium = -1.66 V
In a galvanic cell the component with lower standard reduction potential gets oxidized and that it is added to the anode compartment. 
Therefore. the voltage of a galvanic cell made with zinc and aluminium will be;
Voltage =Ered- Eoxd
             = -0.76 - (-1.66)
             = 0.9 V
6 0
3 years ago
Read 2 more answers
Which of the following is an expression of Charles's law?
HACTEHA [7]

Answer:

C.

Explanation:

V/T

4 0
3 years ago
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