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grin007 [14]
3 years ago
8

A 5,000 kg truck moving at 8 m/s has the same momentum as a 2,500 kg car. What is the velocity of the car?

Physics
1 answer:
rodikova [14]3 years ago
5 0

Answer:

16 m/s.

Explanation:

The following data were obtained from the question:

Mass of truck = 5000 Kg

Velocity of truck = 8 m/s

Mass of car = 2500 kg

Velocity of car =..?

Next, we shall determine the momentum of the truck. This can be obtained as follow:

Mass of truck = 5000 Kg

Velocity of truck = 8 m/s

Momentum of truck =.?

Momentum = mass × velocity

Momentum = 5000 × 8

Momentum of the truck = 40000 Kg.m/s

Finally, we shall determine the velocity of the car as follow:

From the question given above, we were told that the car and truck has the same momentum.

This implies that:

Momentum of the truck = momentum of car = 40000 Kg.m/s

Thus, the velocity of the car can be obtained as shown below:

Mass of car = 2500 kg

Momentum of the car = 40000 Kg.m/s

Velocity of car =..?

Momentum = mass × velocity

40000 = 2500 × velocity

Divide both side by 2500

Velocity = 40000/2500

Velocity = 16 m/s

Therefore, the velocity of the car is 16 m/s.

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Consider the graph below that represents the variation of the velocity with respect to time of an object moving along the x - ax
vazorg [7]

In a velocity-time graph, the area under the curve represents the distance.

The distance traveled from 10s to 18 s is

\begin{gathered} d\text{ = }\frac{1}{2}\times10\times(18-10) \\ =\text{ 40 m} \end{gathered}

Final Answer: The distance traveled is 40 m from time 10 s to 18 s.

3 0
1 year ago
What is the law of variation of the period T of a simple pendulum
DIA [1.3K]
The period of a simple pendulum is given by:
T=2 \pi  \sqrt{ \frac{L}{g} }
where L is the length of the pendulum and g=9.81 m/s^2 is the gravitational acceleration. As we can see, the period of a simple pendulum depends only on its length.
3 0
3 years ago
Cathode ray particles have what type of charge
zlopas [31]

Answer:

negative charge

Explanation:

3 0
2 years ago
What is the average power dissipated by a resistor of resistance R = 25 Ω in an LRC circuit for which the power factor is equal
olga55 [171]

Answer:

0.08 w

Explanation:

AVERAGE POWER : Average power is defined as the average work per unit time. average power is denoted by P its depend on the voltage current and power factor.

the expression for the average power is given as

P=V_rI_r cosΦ

We have given maximum voltage =8 volt

V_r=\frac{8}{1.414}

power factor =.25

resistance =25Ω

power factor =\frac{R}{Z}

power factor=\frac{25}{Z}

From here Z=100

P=\frac{8}{1.414} ×\frac{v_r}{Z} ×cosΦ

=5.6577×0.05677×0.25

=0.08w

3 0
3 years ago
From a hot air balloon 2 km​ high, a person looks east and sees one town with angle of depression of 16 degrees. He then looks w
Dafna1 [17]

Answer:

7km

Explanation:

The angle of depression is congruent to the angle of elevation and can be explained as angle below horizontal in which the person observing an object must view for him/her to view object's that are lower than him/her.

In angle of depression, there is assumption that object is closer to the person observing it, so there is parallel horizontal for both observing and object been observed.

hot air balloon 2 km​ high,

there exist two triangles

From trigonometry

Tanx= opposite/adjacent

Opp= 2km

Adj= X1

first triangle have base length of

Tan(16)=2/X1

X1=2/ tan(16)

X1=6.97

For Second triangle

Tanx= opposite/adjacent

Opp= 2km

Adj= X2

the other with a base length of

X2=2/tan(84)

X2=0.21

Therefore,, the total distance between the two towns is

x1+x2=6.97+0.21=7.18km

6 0
3 years ago
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