All categories

3 years ago

A 5,000 kg truck moving at 8 m/s has the same momentum as a 2,500 kg car. What is the velocity of the car?

Physics

1 answer:

rodikova [14]3 years ago

5 0

Answer:

16 m/s.

Explanation:

The following data were obtained from the question:

Mass of truck = 5000 Kg

Velocity of truck = 8 m/s

Mass of car = 2500 kg

Velocity of car =..?

Next, we shall determine the momentum of the truck. This can be obtained as follow:

Mass of truck = 5000 Kg

Velocity of truck = 8 m/s

Momentum of truck =.?

Momentum = mass × velocity

Momentum = 5000 × 8

Momentum of the truck = 40000 Kg.m/s

Finally, we shall determine the velocity of the car as follow:

From the question given above, we were told that the car and truck has the same momentum.

This implies that:

Momentum of the truck = momentum of car = 40000 Kg.m/s

Thus, the velocity of the car can be obtained as shown below:

Mass of car = 2500 kg

Momentum of the car = 40000 Kg.m/s

Velocity of car =..?

Momentum = mass × velocity

40000 = 2500 × velocity

Divide both side by 2500

Velocity = 40000/2500

Velocity = 16 m/s

Therefore, the velocity of the car is 16 m/s.

You might be interested in

The velocity of the block at the bottom of the incline at point B

neonofarm [45]

Not enough information is given to answer this question.

3 0

3 years ago

Moira is drawing the electric field lines around a pair of charges. One charge is positive, and the other charge is negative.

Romashka-Z-Leto [24]

The best answer is B. If you curve them away, they have a less tendency to be attracted to the pair of charges and would stay around the pair instead of interacting with them.

8 0

3 years ago

A 0.0382-kg bullet is fired horizontally into a 3.78-kg wooden block attached to one end of a massless, horizontal spring (k = 8

wel

Answer:

$280.87$ ms⁻¹

Explanation:

Consider the motion of the bullet-block combination after collision

$m$ = mass of the bullet = 0.0382 kg

$M$ = mass of wooden block = 3.78 kg

$V$ = velocity of the bullet-block combination after collision

$k$ = spring constant of the spring = 833 N m⁻¹

$A$ = Amplitude of oscillation = 0.190 m

Using conservation of energy

Kinetic energy of bullet-block combination after collision = Spring potential energy gained due to compression of spring

$(0.5)(m + M)V^{2} = (0.5)kA^{2}$

$(0.0382 + 3.78)V^{2} = (833)(0.190)^{2}$

$V = 2.81$ ms⁻¹

$v_{o}$ = initial velocity of the bullet before striking the block

Using conservation of momentum for the collision between bullet and block

$m v_{o} = (m + M) V$

$(0.0382) v_{o} = (0.0382 + 3.78) (2.81)$

$v_{o} = 280.87$ ms⁻¹

7 0

3 years ago

How many minutes would it take a light wave to travel from the planet Venus to Earth? (Average distance from Venus to Earth = 28

Gnesinka [82]

Answer:

$t=2.51min$

Explanation:

The time taken by the light to travel a given distance is defined as:

$t=\frac{d}{c}$

Here c is obviously the speed of light. Now we convert the average distance form Venus to Earth to meters:

$28*10^{6}mi*\frac{1609.34}{1mi}=4.51*10^{10}m$

Finally, we calculate the minutes taken by the light to travel from Venus to Earth:

$t=\frac{4.51*10^{10}m}{3*10^8\frac{m}{s}}\\t=150.33s*\frac{1min}{60s}=2.51min$

6 0

3 years ago

What's an easy way to create an interference pattern of waves?

igor_vitrenko [27]

Answer:

Explanation:

5 0

3 years ago