The sentence is accurate, therefore TRUE is the answer.
The total work done on the car is 784Joule.
<h3>What's the acceleration of the car?</h3>
- As per Newton's equation of motion, V= U+at
- U= initial velocity= 0 m/s
V= vinal velocity= 20m/s
t= time = 10s
a= acceleration
=> a= 20/10= 2m/s²
<h3>What's the distance covered by the car in 10 seconds?</h3>
- As per Newton's equation of motion,
V²-U² = 2aS
- S= distance covered by the car
- So, 20²-0=2×2×S=4S
=> 400= 4S
=> S= 400/4= 100m
<h3>What's the work done on the car due to frictional force?</h3>
Work done by frictional force= frictional force × distance
= (0.2×4×9.8)×100
= 784Joule
Thus, we can conclude that the work done on the car is 784Joule.
Learn more about the work done here:
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The impact speed will be
v^2 = 2*9.8*1.3
v^2 = 25.48
v= 5.04 m/s
Answer:
answer E
Explanation:
cuz its 45 is divisible by 3 and 5 but not 10
Answer:
I think it would be GFI outlet
Explanation:
Ground Fault Circuit Interrupter (GFI) device protects us from receiving electric shocks from faults in the electrical devices we use in our home. (resource Google)