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Vinvika [58]
3 years ago
14

How to find the diameter of a circle when the distance is given

Mathematics
1 answer:
jenyasd209 [6]3 years ago
4 0

Answer:

d=2r

d=A/pi

hope it helps

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Find the value of a that makes the following equation true for all values of x 0.9^60x=a^x
MrRissso [65]

Step-by-step explanation:

I am new to brainly plz help me bro

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7 0
3 years ago
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Area of Composite Figures
AlekseyPX

Answer:

1) 147

2) 87m^{2}  

Step-by-step explanation:

1) Area of triangle = × base length × height

= \frac{1}{2} × 14 × 10

= 70 m^{2}

Area of a semicircle = \frac{\pi r^{2} }{2} ( r is the radius)

Radius = half of diameter = \frac{14}{2} = 7m

Area of semicircle = \frac{\pi 7^{2} }{2} = \frac{\pi49 }{2}

= 77m^{2} ( Nearest whole number )

Total area = 77 + 70 = 147m^{2}

2) Divide the shape into 2 rectangles

Area of a rectangle = length × width

Rectangle 1 = 7 × ( 3+3+5 )

= 7 × 11 = 77m^{2}

Rectangle 2 = 2 × 5

= 10m^{2}

Total Area = 77 + 10 = 87m^{2}

8 0
3 years ago
Read 2 more answers
What is the distance from the origin (0,0) to the point (34,-78)
pantera1 [17]

Given coordinates (0,0)  and (34,-78).

\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

We \ have\ x_1=0, x_2=34, y_1=0 \ and \ y_2=-78.

\mathrm{The\:distance\:between\:}\left(0,\:0\right)\mathrm{\:and\:}\left(34,\:-78\right)\mathrm{\:is\:}

=\sqrt{\left(34-0\right)^2+\left(-78-0\right)^2}

=2\sqrt{1810}

Distance = 2(42.544) ≈ 85.09.

Therefore, distance from the origin (0,0) to the point (34,-78) is 2\sqrt{1810} \ or 85.09 units.


3 0
3 years ago
20 points!!!! please help fast!!!!
Lady_Fox [76]

Answer:

0 m/s

Step-by-step explanation:

The line is flat so there is no movement

7 0
3 years ago
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For which of the following are x=4 and x=-4 solutions?
ELEN [110]

Answer:

2x2 - 5x - 12 = 0.

(2x + 3)(x - 4) = 0.

2x + 3 = 0 or x - 4 = 0.

x = -3/2, or x = 4. I hope this helps

Step-by-step explanation:

5 0
3 years ago
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