Answer:
2 sqrt(5) OR 4.5
Step-by-step explanation:
You have to know Pythagorean theorem to solve this question.
a^2 + b^2 = c^2
To use this theorem you have to have a right triangle. There are two right triangles in your image. The lower (larger) one has two sides labeled, so you can use Pythagorean thm to find the third side. There's a short cut, bc some right triangles have easy-to-memorize lengths of the sides. 3-4-5 is one of these number sets. A multiple of this is 6-8-10. We could've solved:
b^2 + 8^2 = 10^2
But it would've come out the same. The unlabeled side is 6.
We can use the 6 and the 4 on the smaller right triangle and use the Pythagorean thm again to solve for x.
4^2 + x^2 = 6^2
16 + x^2 = 36 subtract 16 from both sides.
x^2 = 20
Take the square root of both sides.
sqrt (x^2) = sqrt 20
x = 2 sqrt(5) which is approximately 4.472.
2 sqrt(5) is an exact answer if that is what they are asking for. 4.472 is an approximation to the nearest thousandth. It would be 4.47 to the nearest hundredth or 4.5 to the nearest tenth.
Answer:
4th row will result in the greatest mean.
Step-by-step explanation:
We are asked to find the row with greatest mean from our given rows.
We will use formula 
, where,
,
,
Let us find mean of each row using above formula.
Therefore, mean of 1st row is 2.8.
Therefore, mean of 2nd row is 3.
Therefore, mean of 3rd row is 3.2.
Therefore, mean of 4th row is 4.2.
Since 4th row has the highest mean, therefore, 4th row will result in the greatest mean.
A = event the person got the class they wanted
B = event the person is on the honor roll
P(A) = (number who got the class they wanted)/(number total)
P(A) = 379/500
P(A) = 0.758
There's a 75.8% chance someone will get the class they want
Let's see if being on the honor roll changes the probability we just found
So we want to compute P(A | B). If it is equal to P(A), then being on the honor roll does not change P(A).
---------------
A and B = someone got the class they want and they're on the honor roll
P(A and B) = 64/500
P(A and B) = 0.128
P(B) = 144/500
P(B) = 0.288
P(A | B) = P(A and B)/P(B)
P(A | B) = 0.128/0.288
P(A | B) = 0.44 approximately
This is what you have shown in your steps. This means if we know the person is on the honor roll, then they have a 44% chance of getting the class they want.
Those on the honor roll are at a disadvantage to getting their requested class. Perhaps the thinking is that the honor roll students can handle harder or less popular teachers.
Regardless of motivations, being on the honor roll changes the probability of getting the class you want. So Alex is correct in thinking the honor roll students have a disadvantage. Everything would be fair if P(A | B) = P(A) showing that events A and B are independent. That is not the case here so the events are linked somehow.
Answer:
Step-by-step explanation:
(6/5)√x = x - 6
(36/25)x = x² - 12x + 36
0 = x² - 13.44x + 36
x = (13.44 ± √(13.44² - 4(1)(36))) / (2(1))
x = (13.44 ± 6.052569702...) / 2
x = 3.69371... zebras
or
x = 9.74628... zebras
In either case we have some odd fractions of zebras hanging around. This makes me highly suspect that the question is misreported
