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3 years ago

Which one of the following is the net ionic equation for the reaction of nitric acid with aluminum hydroxide

1 answer:

5 0

The ionic eqn is as follow:

1 Al(OH)3(s) + 3 H+(aq) + 3 NO3(-1) --> 1 Al(3+)(aq) + 3 NO3(-)(aq) + 3 H2O(l)

3moles of No3- ion on both sides cancels out to give the net ionic eqn:

1 Al(OH)3(s) + 3 H+(aq) --> 1 Al(3+)(aq) + 3 H2O(l)

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What do you get if you do zinc and aluminum chloride

olchik [2.2K]

Zinc chloride and aluminum

5 0

3 years ago

100.0 mL of 3.8M NaCN, the minimum lethal concentration of sodium cyanide in blood serum

9966 [12]

The given question is incomplete. The complete question is:

Calculate the number of moles and the mass of the solute in each of the following solution: 100.0 mL of 3.8 × 10−5 M NaCN, the minimum lethal concentration of sodium cyanide in blood serum

Answer: The number of moles and the mass of the solute are $0.38\times 10^{-5}$ and $18.62\times 10^{-5}g$ respectively

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in ml

$3.8\times 10^{-5}M=\frac{n\times 1000}{100.0}$

$n=0.38\times 10^{-5}$

n = moles of $NaCN$ = $\frac{\text {given mass}}{\text {Molar mass}}$

$0.38\times 10^{-5}=\frac{x}{49g/mol}$

$x=18.62\times 10^{-5}g$

Thus the number of moles and the mass of the solute are $0.38\times 10^{-5}$ and $18.62\times 10^{-5}g$ respectively

6 0

3 years ago

Most Bic lighters hold 5.0ml of liquified butane (density = 0.60 g/ml). Calculate the minimum size container you would need to "

Hatshy [7]

Answer:

Volume of container = 0.0012 m³ or 1.2 L or 1200 ml

Explanation:

Volume of butane = 5.0 ml

density = 0.60 g/ml

Room temperature (T) = 293.15 K

Normal pressure (P) = 1 atm = 101,325 pa

Ideal gas constant (R) = 8.3145 J/mole.K)

volume of container V = ?

Solution

To find out the volume of container we use ideal gas equation

PV = nRT

P = pressure

V = volume

n = number of moles

R = gas constant

T = temperature

First we find out number of moles

As Mass = density × volume

mass of butane = 0.60 g/ml ×5.0 ml

mass of butane = 3 g

now find out number of moles (n)

n = mass / molar mass

n = 3 g / 58.12 g/mol

n = 0.05 mol

Now put all values in ideal gas equation

PV = nRt

V = nRT/P

V = (0.05 mol × 8.3145 J/mol.K × 293.15 K) ÷ 101,325 pa

V = 121.87 ÷ 101,325 pa

V = 0.0012 m³ OR 1.2 L OR 1200 ml

8 0

4 years ago

Which of the following is a balanced equation for Copper (II) sulfate + aluminum --> aluminum sulfate+solid copper?

artcher [175]

3 CuSO4(aq)+2Al(s) -->Al2(SO4)3(aq)+Cu(s) is a balanced equation for Copper (II) sulfate + aluminum --> aluminum sulfate+solid copper. The correct answer between all the choices given is the second choice or letter B. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

5 0

4 years ago

How many moles of water were lost if the amount of water lost was 0.294 grams?

olga55 [171]

0.01631973355 is your answer. Have a great day and hope this helps!!!

7 0

3 years ago