What information would you need to determine the most likely resonance structure for the molecule?

CO, + H2O –H^2 CO^3 The reaction is which type of chemical reaction?

gulaghasi [49]

Answer:

Combination reaction or synthesis reaction

Explanation:

Given reaction:

CO + H₂O → H₂CO₃

The type of reaction shown above is a combination or synthesis reaction. A combination reaction is one in which a single product is formed from two or more reactants.

In the given reaction carbon monoxide combines with water to produce hydrogen carbonate.

The formation of compounds from the union of their constituent elements falls into this category of reactions.

4 0

2 years ago

A sample of chlorine gas fills a vessel at a temperature of 37oC. The vessel has a volume of 3L and experiences a pressure of 3a

Iteru [2.4K]

Answer:

25.1 g is the mass of chlorine in the sample

Explanation:

P . V = n . R . T

We apply the Ideal Gases Law to solve the excersise.

We need to convert the T°C to T°K → 37°C + 273 = 310K

We replace data: 3 atm . 3L = n . 0.082 L.atm /mol.K . 310K

9 atm.L / (0.082 L.atm /mol.K . 310K) = n → 0.354 moles

We convert the moles to mass, to reach the answer

0.345 mol . 70.9g / 1mol = 25.1 g

7 0

3 years ago

A second- order reaction of the type A + B -->P was carried out in a solution that was initially 0.075 mol dm^-3 in A and 0.0

andriy [413]

Answer:

a) 16.2 dm^3/mol*h

b) 6.1 × 10^3 s, 2.5 × 10^3 s (it is different to the hint)

Explanation:

We can use the integrated rate equation in order to obtain k.

For the reaction A+ B --> P the reaction rate is written as

Rate = $-\frac{dC_A}{dt} = -\frac{dC_B}{dt} = \frac{dC_P}{dt} = kC_AC_B$

If $C_{A0}$ and $C_{B0}$ are the inital concentrations and x the concentration reacted at time t, so $C_A=C_{A0} -x$ and $C_B=C_{B0} -x$ and the rate at time t is written as:

$-\frac{dx}{dt} =-k(C_{A0} -x)(C_{B0}-x)$

Separating variables and integrating

$\int\limits^x_0 {\frac{1}{(C_{A0}-x)(C_{B0}-x)} } \, dx = \int\limits^t_0 {k} \, dt$

The integral in left side is solved by partial fractions, it can be used integral tables

$\frac{1}{C_{B0}-C_{A0}}(ln\frac{C_{A0}}{C_{A0}-x}-ln\frac{C_{B0}}{C_{B0}-x}) =kt$

Using logarithm properties (ln x - ln y = ln(x/y))

$\frac{1}{C_{B0}-C_{A0}}(ln\frac{C_{A0}C_{B}}{C_{A}C_{B0}}) =kt$

Using the given values k can be calculated. But the data seems inconsistent since if the concentration of A changes from 0.075 to 0.02 mol dm^-3 it implies that 0.055 mol dm^-3 of A have reacted after 1 h, so according to the reaction given the same quantity of B should react, and we only have a $C_{B0}$ of 0.05 mol dm^-3.

Assuming that the concentration of B fall to 0.02 mol dm^-3 (and not the concentration the A). So we arrive to the answer given in the Hint.

So, the values given are t= 1, $C_{A0}=0.075$ , $C_{B0}=0.05$ , $C_{B}=0.02$ , it implies that the quantity reacted, x, is 0.03 and $C_{A}=0.075-x = 0.045$ . Then, the value of k would be

$kt = \frac{1}{0.05-0.075}(ln\frac{0.075*0.02}{0.045*0.05})$

$k = 16.21 \frac{dm^3}{mol*1h}$

b) the question b requires calculate the time when the concentration of the specie is half of the initial concentration.

For reactant A, It is solved with the same equation

$\frac{1}{C_{B0}-C_{A0}}(ln\frac{C_{A0}C_{B}}{C_{A}C_{B0}}) =kt$

but suppossing that $C_A= C_{A0}/2=0.0375$ so $C_B=C_{B0}- C_{A0}/2=0.0125$ , k=16.2 and the same initial concentrations. Replacing in the equation

$t=\frac{1}{16.2(0.05-0.075)}(ln\frac{0.075*0.0125}{0.0375*0.05})$

$t=1.71 h = 1.71*3600 s = 6.1*10^3 s$

For reactant B, $C_B= C_{B0}/2=0.025$ so $C_A=C_{A0}- C_{B0}/2=0.05$ , k=16.2 and the same initial concentrations. Replacing in the equation

$t=\frac{1}{16.2(0.05-0.075)}(ln\frac{0.075*0.025}{0.05*0.05})$

$t=0.71 h = 0.7*3600 s = 2.5*10^3 s$

Note: The procedure presented is correct, despite of the answer be something different to the given in the hint, I obtain that result if the k is 19.2... (maybe an error in calculation of given numbers)

3 0

2 years ago

Which of the following would most likely happen if average global temperatures on Earth increased?

iragen [17]

Answer:

D. severe weather events would occur more often

Explanation:

If the average global temperatures on Earth increased, there are high chances of severe weather events occurring more often

Weather events are devastating in nature.
Examples are hail, blizzards, Lightning and thunderstorm

Increase in average global temperatures can result in these disasters.

When global temperatures increases, polar ice will melt and sea levels will increase.

This will cause storms in coastal areas and flooding.

3 0

3 years ago

The middle ear converts sound from what into vibrations that can be sent through what?

Katarina [22]

Answer:

.

Explanation:

Eardrum or tympanic membrane changes sound to vibration and pass through malleus, incus and stapes.

5 0

3 years ago