Question

Students are using the experimental setup shown in the image in which the two ends of a string are attached to a car and to a hanger. The students conduct three trials in which they place metal discs on the hanger to manipulate the force applied to the car. As a result, the car accelerates along with the table while two probes collect motion data.
On the fourth trial of this experiment, a student places some discs on the car by mistake. In 1-2 sentences, explain how this mistake will affect the graphs produced by the computer.

Answer 1

Answer:

i used the answer above and got

Explanation:

Answer 2

The Newton's second law and kinematics allows to find the result of the error when placing the masses in the car is:

• Acceleration decreases.

• The plot of position vs. time squared is still linear, but the slope is less.

     

Newton's second law gives a relationship between the net force, mass and acceleration of the body

      F = ma

      a = $\frac{F}{m}$

Where F is the force, m the mass and the acceleration

 

Kinematics studies the motion of bodies, looking for relationships between position, velocity, and acceleration.

         x = v₀ t + ½ a t²

In the experiment, the position and time of the car are measured, starting from rest in each experiment.

        x = ½ a t²

Let's substitute

      x =  ½ ( $\frac{F}{m}$ ) t²

This is the equation that the students should graph, a graph of the position versus time squared can be made to obtain a line.

The slope of the line is the acceleration of the car, which is related to the force that is the weight of the hanging mass.

When the student makes the mistake of placing the mass on the car, the acceleration decreases therefore in a graph the position values ​​are smaller for each time.

The linearity of the graph is maintained, but when calculating the slope it gives lower values.

In conclusion using Newton's second law and kinematics we can find the result of the error when placing the masses on the car is:

• Acceleration decreases.

• The plot of position vs. time squared is still linear, but the slope is less.

Learn more here: brainly.com/question/11298125