Answer:
121.63 g/mol
Explanation:
Sr(OH) 2 = Strontium Hydroxide
Answer:
Sn and Ge
Explanation:
To obtain the more metallic element, we compare the group in which both elements are. Generally the element with the lower ionzation energy is he more metallic one.
Ionization energy increases fro left to right across a period. Ionization energy decreases down the group.
1. When comparing the two elements A s and S n , the more metallic element is ______based on periodic trends alone.
Sn has a lower ionization energy so it is the more metallic one.
2. When comparing the two elements G e and S b , the more metallic element is ________ based on periodic trends alone.
Ge has a lower ionizaiton energy compared to Sb. So it is more metallic element than Sb.
Answer:
Yes
Explanation:
Let's write the reaction as
CV⁺+ OH⁻ ⟶ CVOH
The reaction is first order in [CV⁺] and in [OH⁻], so the rate law is
rate = k[CV⁺][OH⁻]
A bimolecular collision between a crystal violet ion and a hydroxide ion as an elementary step would predict the observed rate law.
However, other plausible mechanisms may predict the same rate law.
