The correct answer is C. An example of measurement bias in scientific
measurement, of the available answers, would be a balance that always
reads 0.1g. The other possible answers are all examples of devices or
measurement techniques that would help a scientist to avoid measurement
bias, rather than contributing to it.
Answer:
D.
Explanation:
Although all of these answers are similar, it seems that all three are the answer. I am sorry if the answer ends up being B but I'm pretty sure the answer is D. Charles Darwin's evolution theory "evolved", get it, from the natural selection theory. The theory is described as "the process whereby organisms better adapted to their environment tend to survive and produce more offspring." However, some factors that effect natural selection are competition, selection and variation. I believe all three fit the answer and therefore I believe answer D is correct.
Answer:
0.4515 M
Explanation:
In case of titration , the following formula can be used -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid ,
M₂ = concentration of base,
V₂ = volume of base .
from , the question ,
M₁ = ? M
V₁ = 10.0 mL
M₂ = 0.100 M
V₂ = 45.15 mL
Using the above formula , the molarity of acid , can be calculated as ,
M₁V₁ = M₂V₂
M₁ * 10.0mL = 0.100 M * 45.15 mL
M₁ = 0.4515 M
Hence, the concentration of the acetic acid = 0.4515 M
The reaction of acetic acid with sodium hydroxide is:

The ratio of A-/HA is calculated as follows:
According to Henderson Hasslebach equation:
![[A-]/[HA] = 10^p^H^-^p^K^_a](https://tex.z-dn.net/?f=%5BA-%5D%2F%5BHA%5D%20%3D%2010%5Ep%5EH%5E-%5Ep%5EK%5E_a)

The total concentration of HA and A- = 2.0 L * 0.25 M = 0.5 mol.
![[ A- ]+ [ HA ]= 0.5](https://tex.z-dn.net/?f=%5B%20A-%20%5D%2B%20%5B%20HA%20%5D%3D%200.5)
![[ A^- ] = 0.5 – [ HA]](https://tex.z-dn.net/?f=%5B%20A%5E-%20%5D%20%3D%200.5%20%E2%80%93%20%5B%20HA%5D)
[ HA] = 0.156 mol and [ A- ]= 0.343 mol
Total of 0.5 moles of acetic acid is required:

HA = 30.0 g acetic acid
Conversion of 0.343 moles of the acetic acid to acetate can be performed by adding NaOH

= 343 mL
Thus, 343 mL of 1M NaOH is required