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3 years ago

What's the answer to this conversion? : 300 K to °C

Chemistry

2 answers:

Katyanochek1 [597]3 years ago

7 0

Answer:

Hey!

Your answer is 26.85 C

Explanation:

To convert from K to C JUST SUBTRACT 273.15!

300 - 273.15 = 26.85

ANSWER : 26.85 C

natali 33 [55]3 years ago

7 0

I think the conversion is: 26.85°C

I hope this helped! Sorry if you get this wrong! :)

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Assuming a car (with a 70-L) gas tank can hold approximately 50,000 (5.00 * 10^4) g of octane(C8H18) or 50,000 (5.00 * 10^4) g o

konstantin123 [22]

Answer:

- From octane: $m_{CO_2}=1.54x10^5gCO_2$

- From ethanol: $m_{CO_2}=9.57x10^4gCO_2$

Explanation:

Hello,

At first, for the combustion of octane, the following chemical reaction is carried out:

$C_8H_{18}+\frac{25}{2} O_2\rightarrow 8CO_2+9H_2O$

Thus, the produced mass of carbon dioxide is:

$m_{CO_2}=5.00x10^4gC_8H_{18}*\frac{1molC_8H_{18}}{114gC_8H_{18}}*\frac{8molCO_2}{1molC_8H_{18}}*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=1.54x10^5gCO_2$

Now, for ethanol:

$C_2H_6O+3O_2\rightarrow 2CO_2+3H_2O$

$m_{CO_2}=5.00x10^4gC_2H_6O*\frac{1molC_2H_6O}{46gC_2H_6O}*\frac{2molCO_2}{1molC_2H_6O}*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=9.57x10^4gCO_2$

Best regards.

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3 years ago

A chemist determines by measurements that moles of nitrogen gas participate in a chemical reaction. Calculate the mass of nitrog

Likurg_2 [28]

Answer:

0.56 g

Explanation:

A chemist determines by measurements that 0.020 moles of nitrogen gas participate in a chemical reaction. Calculate the mass of nitrogen gas that participates.

Step 1: Given data

Moles of nitrogen gas (n): 0.020 mol

Step 2: Calculate the molar mass (M) of nitrogen gas

Molecular nitrogen is a gas formed by diatomic molecules, whose chemical formula is N₂. Its molar mass is:

M(N₂) = 2 × M(N) = 2 × 14.01 g/mol = 28.02 g/mol

Step 3: Calculate the mass (m) corresponding to 0 0.020 moles of nitrogen gas

We will use the following expression.

m = n × M

m = 0.020 mol × 28.02 g/mol

m = 0.56 g

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3 years ago

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2 years ago

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Montano1993 [528]

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