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aliya0001 [1]
3 years ago
10

1S Called A simple machine that has a disc with a grooved rim to wind up asing is called When a fixed pulley and a movable nugnk

cmm vnghldley​
Chemistry
2 answers:
EastWind [94]3 years ago
7 0

Answer:

the question isn't enlisted here...

maxonik [38]3 years ago
3 0

what is the question??

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Which of the following is not a part of every scientific investigation?
Dmitry_Shevchenko [17]

Answer:

the correct answer is Group of answer choices

6 0
3 years ago
If 60 grams of a liquid takes up 120ml how dense is the liquid
Black_prince [1.1K]

Answer:

<h2>Density = 0.5 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

<h3>Density =  \frac{mass}{volume}</h3>

From the question

mass = 60 g

volume = 120 mL

Substitute the values into the above formula and solve

That's

<h3>Density =  \frac{60}{120}  \\  =  \frac{1}{2}</h3>

We have the final answer as

<h3>Density = 0.5 g/mL</h3>

Hope this helps you

4 0
3 years ago
Water can act as both an acid and a base in an ionization reaction to form (H) and OH ions.
matrenka [14]
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4 0
3 years ago
Read 2 more answers
Turn on Write equation. What you see is an equation that shows the original uranium atom on the left. The boxes on the right rep
My name is Ann [436]

Answer:

Uranium-238 undergoes alpha decay to form Thorium-234 as daughter product.

Explanation:

Alpha decay is indicative of loss of the equivalents of a helium particle emission. The reaction equation for this reaction is shown below:

_{92} ^{238} U_{}→ _{90} ^{234} Th_{} + _{2} ^{4} He_{}

I hope this explanation is clear and explanatory.

6 0
3 years ago
If 10.0 mL of a .600 M of HNO3 reacts with 31.0 mL of .700M Ba(OH)2 solution, what is the molarity of Ba(OH)2 after the reaction
Tasya [4]

Answer:

<u></u>

  • <u>0.456M</u>

Explanation:

<u>1. Balanced molecular equation</u>

     2HNO_3+Ba(OH)_2\rightarrow Ba(NO_3)_2+2H_2O

<u>2. Mole ratio</u>

     \dfrac{2molHNO_3}{1molBa(OH)_2}

<u>3. Moles of HNO₃</u>

  • Number of moles = Molarity × Volume in liters
  • n = 0.600M × 0.0100 liter = 0.00600 mol HNO₃

<u>4. Moles Ba(OH)₂</u>

  • n = 0.700M × 0.0310 liter = 0.0217 mol

<u>5. Limiting reactant</u>

Actual ratio:

   \dfrac{0.0600molHNO_3}{0.0217molBa(OH)_2}\approx0.28

Since the ratio of the moles of HNO₃ available to the moles of Ba(OH)₂ available is less than the theoretical mole ratio, HNO₃ is the limiting reactant.

Thus, 0.006 moles of HNO₃ will react completely with 0.003 moles of Ba(OH)₂ and 0.0217 - 0.003 = 0.0187 moles will be left over.

<u>6. Final molarity of Ba(OH)₂</u>

  • Molarity = number of moles / volume in liters
  • Molarity = 0.0187 mol / (0.0100 + 0.0031) liter = 0.456M
5 0
3 years ago
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