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Zinaida [17]
3 years ago
13

In a 40-day period, at least one bear was observed by a camper in a designated camp site on 28 separate days. According to this

information, what is the daily frequency of bear sightings (in which at least one bear is observed)?. A.143%. B.70%. C.28%. D. 40%
Mathematics
2 answers:
tatyana61 [14]3 years ago
6 0

Answer:

B. 70%

Step-by-step explanation:

Have a nice day :).

olasank [31]3 years ago
5 0
<span>At least one bear was sighted on 28 separate days in 40 day period total = 28/40
We're looking for the daily frequency of bear sightings, that's in the whole 40 day period. 

Let's say 40 days period = 100%.
Then what's 28 days?
</span>

So the solution we're looking for would be (<span><span>28 days∗100) / </span>40 days = 70%</span>

The final answer is B. 70%.

<span>
</span>

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Answer:

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Step-by-step explanation:

Formula we use,

→ A + B + C + D + E = 540°

Then the value of x will be,

→ A + B + C + D + E = 540°

→ (6x + 25°) + (5x + 10°) + (3x - 5°) + (5x + 10°) + (6x + 25°) = 540°

→ (6x + 5x + 3x + 5x + 6x) + (25° + 10° - 5° + 10° + 25°) = 540°

→ 25x + 65° = 540°

→ 25x = 540° - 65°

→ 25x = 475°

→ x = 475/25

→ [ x = 19° ]

The value of angle (3x - 5°) will be,

→ (3x - 5°)

→ (3 × 19) - 5°

→ 57° - 5°

→ [ 52° ]

Hence, value of angle (3x - 5°) is 52°.

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2 years ago
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Try this option:

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Answer:

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Step-by-step explanation:

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