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Zinaida [17]
3 years ago
13

In a 40-day period, at least one bear was observed by a camper in a designated camp site on 28 separate days. According to this

information, what is the daily frequency of bear sightings (in which at least one bear is observed)?. A.143%. B.70%. C.28%. D. 40%
Mathematics
2 answers:
tatyana61 [14]3 years ago
6 0

Answer:

B. 70%

Step-by-step explanation:

Have a nice day :).

olasank [31]3 years ago
5 0
<span>At least one bear was sighted on 28 separate days in 40 day period total = 28/40
We're looking for the daily frequency of bear sightings, that's in the whole 40 day period. 

Let's say 40 days period = 100%.
Then what's 28 days?
</span>

So the solution we're looking for would be (<span><span>28 days∗100) / </span>40 days = 70%</span>

The final answer is B. 70%.

<span>
</span>

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Answer:

cost of system is $175 and cost of the games is $525

Step-by-step explanation:

Let us take the cost of the system to be X.The games cost 3 times as much as the system and are therefore given 3X. The total cost of the system and the games is $700.Therefore,we form the equation 3X+X=$700.Meaning that 4X=$700 and X is equal to $175.The cost of the system is X therefore it is $175 and the cost of the games is 3X and is therefore $525.

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Answer:

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Step-by-step explanation:

Step 1:

0.6x - 0.1 = 0.5x + 2      Equation

Step 2:

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Step 3:

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Step 4:

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Complete question:

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Answer:

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