Answer:
l=5.12 & w=2.62
Step by step explanation:
A=l×w
13.42=lw
w=13.42/l

Since you have found the value of the length you can find the value.of the width.

Answer:
J(2, 5 )
Step-by-step explanation:
Using the section formula
=
=
=
= 2
=
=
=
= 5
Thus J = (2, 5 )
Answer:
I believe the answer is D
From what I think;
8.216secs - 1 wheel; 3.652- 1 hood
for I toy car with a wheel and hood the total time is 8.216+ 3.652 = 11.868secs
let x secs be the total time taken to put a wheel and hood for 42 cars
x secs = 42 cars × the total time for one car
x secs = 42× 11.868
x secs= 498.456 secs