URGENT, LAST 2 QUESTION!! WILL GIVE BRANLIEST!!! AT LEAST TAKE A LOOK!!

6. The vertices of ALMN are L(7,4), M(7,16), and

max2010maxim [7]

Answer:

(a) LM=12 units, LN=35 units, MN=37 units

(b)8 84 units

(c) 210 square units

Step-by-step explanation:

(a)

Since points L and M have same x coordinates, it means they are in the same plane. Also, since the Y coordinates of L and N are same, they also lie in the same plane

Length $LM=\sqrt {(7-7)^{2}+(16-4)^{2}}=12 units$

Length $LN=\sqrt {(42-7)^{2}+(4-4)^{2}}=35 units$

Length $MN=\sqrt {(42-7)^{2}+(4-16)^{2}}=37 units$

Alternatively, since this is a right angle triangle, length MN is found using Pythagoras theorem where

$MN=\sqrt {(LN)^{2}+(LM)^{2}}=\sqrt {(12)^{2}+(35)^{2}}=37 units$

Therefore, the lengths LM=12 units, LN=35 units and MN=37 units

(b)

Perimeter is the distance all round the figure

P=LM+LN+MN=12 units+35 units+37 units=84 units

(c)

Area of a triangle is given by 0.5bh where b is base and h is height, in this case, b is LN=35 units and h=LM which is 12 units

Therefore, A=0.5*12*35= 210 square units

4 0

3 years ago

What is the length of the unknown leg

likoan [24]

Answer:

6 mm

Step-by-step explanation:

Use the Pythagorean Theorem to solve for the unknown leg

$a^{2} +b^{2}=c^{2}$

Since we need to solve for a, we will manipulate the equation in terms of b and c → $a=\sqrt{c^{2}-b^{2} }$

Here, b = 7 mm and c = $\sqrt{85}$ mm

Plugging these numbers into our equation gives us $a=\sqrt{(\sqrt{85})^{2} -(7)^{2} }$ → $\sqrt{85-49}$ = $\sqrt{36}$ = 6 mm

6 0

3 years ago

What is the perimeter of triangle PQR.

shutvik [7]

Answer:

Opps i am really sorry i donot know it

7 0

3 years ago

Regular hexagon ABCDEF has vertices at A(4, 4!3), B(8, 4!3), C(10, 2!3), D(8, 0), E(4, 0) and F(2, 2!3).

marissa [1.9K]

Since the given hexagon is a regular hexagon all it's sides will be of equal length. Now, we know that the Area of any regular hexagon is given by:

$A=\frac{3\sqrt{3}}{2} a^2$

Where $A$ is the area of the regular hexagon

$a$ is the side length of the regular hexagon

Also, it's Perimeter is given by:

$P=6a$

Thus, all that we need to do is to find the side length of any one of the sides and to do that let us have a look at at the data of vertices points given and find out which points are definitely adjacent to each other and are also easy to calculate.

A quick search will yield that D(8, 0) and E(4, 0) are definitely adjacent to each other.

Please check the attached file here for a better understanding of the diagram of the original regular hexagon. Points D and E indeed are adjacent to each other.

Let us now find the distance between the points D and E using the distance formula which is as:

$d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

Where $d$ is the distance.

$(x_1,y_1)$ and $(x_2,y_2)$ are the coordinates of points D and E respectively. (please note that interchanging the values of the coordinates will not alter the distance $d$ )

Applying the above formula we get:

$d=\sqrt{(8-4)^2+(0-0)^2} =\sqrt{4^2}=4$

$\therefore d=4$

We know that this distance is the side length of the given regular hexagon.

$\therefore d=a=4$

Now, if the sides of the given regular polygon are reduced by 40%, then the new length of the sides will be:

$a_{small}=4-\frac{40}{100}\times 4=2.4$

Thus, the area of the smaller hexagon will be:

$A_{small}=\frac{3\sqrt{3}}{2} a_{small}^2=\frac{3\sqrt{3}}{2} (2.4)^2\approx14.96$ unit squared

and the new smaller perimeter will be:

$P_{small}=6a_{small}=6\times 2.4=14.4$ unit

Which are the required answers.

5 0

3 years ago

Plot 1 goes from 0 to 8. There are 2 images above 5, 2 above 6, 4 above 7, and 5 above 8. Plot 2 goes from 0 to 8. there are 5 i

Mice21 [21]

Answer: the answer is 45

Step-by-step Step-by-step explanation:

so it says a pilot goes from 0 to 8 and then two images above so you add to to eat and then you add 5 to 2:30 for me to 522 the artistic 24 + 27 + 5 then you answer 8 + 2028 and then you add 5 + 1 + 2 + 2 + 4 + 3 + 3 + 4 + 1 + 5 + 16 + 18 and you get 45

5 0

2 years ago