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Greeley [361]
3 years ago
14

Round each decimal number to the nearest hundred 8.314

Mathematics
2 answers:
kobusy [5.1K]3 years ago
6 0

8.31 because it goes after the decimal tenth then hundreth the for is in the thousandths


elixir [45]3 years ago
5 0

The answer is 8.3 Hope this helps

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Solve the equation using the Zero Product Property.
ivolga24 [154]

Answer:

-1.25, 2, 3.5

Step-by-step explanation:

(x-2)(2x-7)(4x+5)=0

(2x^2-7x-4x+14)(4x+5)=5

from now on you know that either

(2x^2-7x-4x+14)=0 or

(4x+5)=0

By solving the first eqation (2x^2-7x-4x+14)=0

you get x = 2 or 3.5

By solving the second equation (4x+5)=0

you get x = -1.25

6 0
4 years ago
Help me out guys. Got stuck over this algebra question ​
vovikov84 [41]

Answer:

Compare LHS and RHS to prove the statement.

Step-by-step explanation:

Given: a + b + c = 0

We have to show that $ \frac{1}{1 + x^b + x^{-c}} + \frac{1}{1 + x^c + x^{-a}} + \frac{1}{1 + x^a + x^{-b}} = 1$

We take LCM, simplify the terms and compare LHS and RHS. We will see that LHS = RHS and the statement will be proved.

Taking LCM, we get:

$ \frac{(1 + x^c + x^{-a})(1 + x^a + x^{-b}) + (1 + x^b + x^{-c})(x^a + x^{-b} + 1) + (x^b + x^{-c} + 1)(x^c + x^{-a} + 1)}{(1 + x^a + x^{-b})(1 + x^b + x^{-c})(1 + x^c + x^{-a})}  $ = 1

⇒ (1 + x^c + x^{-a})(1 + x^a + x^{-b}) + (1 + x^b + x^{-c})(x^a + x^{-b} + 1) + (x^b + x^{-c} + 1)(x^c + x^{-a} + 1)   = (1 + x^a + x^{-b})(1 + x^b + x^{-c})(1 + x^c + x^{-a})

We simplify each term and then compare LHS and RHS.

Simplifying the first term:

(1 + x^c + x^{-a})(1 + x^a + x^{-b})

= $ x^{c + a} + x^{c - b} + x^c +  1 + x^{-a - b} + x^{-a} + x^{a} + x^{-b} + 1 $

= $ x^{c + a} + x^{c - b} + x^{c} + x^{-a - b} + x^{-a} + x^{a} + x^{-b} + 2  \hspace{5mm} \hdots (A)$

Now, we simplify the second term we have:

$ (1 + x^b + x^{-c})(x^a + x^{-b} + 1)  $

= $ x^{a + b} + 1 + x^{b} + x^{a - c} + x^{-b - c} + x^{-c} + x^{a} + x^{-b} + 1 $

= $ x^{a + b} + x^{b} + x^{a - c} + x^{- c - b} + x^{-c} + x^a + x^{-b} + 2 \hspace{5mm} \hdots (B) $

Again, simplifying (x^b + x^{-c} + 1)(x^c + x^{-a} + 1),

= $x^{b + c} + x^{b - a} + x^b + 1 + x^{-c -a} + x^{-c} + x^c + x^{-a} + 1 $

= $ x^{b + c} + x^{b - a} + x^b + x^{-c -a} + x^{-c} + x^c + x^{-a} + 2 $(C)

Therefore, LHS = A + B + C

= $ x^{c + a} + x^{c - b} + 2x^c + x^{-a - b} + 2x^{-a} + 2x^{a} + 2x^{-b} + x^{a + b} + 2x^b + x^{a - c} + x^{-c -b} + x^{b + c} + x^{b - a} + x^{-c -a} + 6 $

Similarly. RHS

= $ (x^{b + c} + x^{b - a} + x^b + 1 + x^{-c -a} + x^{-c} + x^c + x^{-a} + 1)(x^a + x^{-b} + 1) $

Note that if a + b + c = 0, $ \implies x^{a + b + c} = x^0 = 1 $

So, RHS = x^{c + a} + x^{c - b} + 2x^c + x^{-a - b} + 2x^{-a} + 2x^{a} + 2x^{-b} + x^{a + b} + 2x^b + x^{a - c} + x^{-c -b} + x^{b + c} + x^{b - a} + x^{-c -a} + 6

We see that LHS = RHS.

Therefore, the statement is proved.

3 0
4 years ago
Camilias as backyard is in the shape of a rectangle and has a length of 16.5 feet. It costs her $976 to fence in the yard. If fe
Bumek [7]

Answer:

14 feet

Step-by-step explanation:

To calculate the width of the patio, we will use the formula of the perimeter, in the case of the rectangle it has the formula of:

p = 2 * l + 2 * w

Now we know that the total fencing value is $ 976 and that per foot is $ 16

that is, we can calculate the value of the perimeter, like this:

976/16 = 61

We know that the perimeter is 61 feet and that the length is 16.5, therefore it only remains to replace:

61 = 16.5 * 2 + 2 * w

solving for w:

w = (61 - 33) / 2

w = 14

which means that the width of the patio is 14 feet.

8 0
3 years ago
ivy bought 10 packs of cups for her holiday party. a pack of medium cups costs $1.80 and a pack of large cups costs $2.40. she p
DENIUS [597]

Answer:

4 packs of medium cups and 6 packs of large cups

Step-by-step explanation:

1.80x + 2.40y = 21.60

1.80(4) + 2.40(6) = 21.60

7.2 + 14.4 = 21.60

21.60 = 21.60

4 0
4 years ago
Read 2 more answers
How much is the percent increase from 1 to 4?
svetlana [45]

Answer:

300%

Step-by-step explanation:

3 difference increase

5 0
3 years ago
Read 2 more answers
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