Answer:
Depth,
Explanation:
It is given that,
Absorption coefficient,
Surface reflectivity, T = 0.1
Energy of light, E = 3 eV
We need to find the depth at which half the incident optical power has been absorbed in the material. The relationship between the absorption coefficient and intensity of light is given by :
Since, the incident power is becoming half. So,
Since, ln (0.5) = -0.693
x = 0.0000173 m
or
So, the depth at which half the incident optical power has been absorbed in the material is . Hence, this is the required solution.
Answer:
physical change
Explanation:
its a physical change because its still soda it hasn't changed into anything else than what it already is
Answer:
see explanation below
Explanation:
Given that,
500°C
= 25°C
d = 0.2m
L = 10mm = 0.01m
U₀ = 2m/s
Calculate average temperature
262.5 + 273
= 535.5K
From properties of air table A-4 corresponding to = 535.5K
k = 43.9 × 10⁻³W/m.k
v = 47.57 × 10⁻⁶ m²/s
A)
Number for the first strips is equal to
Calculating heat transfer coefficient from the first strip
The rate of convection heat transfer from the first strip is
The rate of convection heat transfer from the fifth trip is equal to
Calculating
The rate of convection heat transfer from the tenth strip is
Calculating
Calculating the rate of convection heat transfer from the tenth strip
The rate of convection heat transfer from 25th strip is equal to
Calculating
Calculating
Calculating the rate of convection heat transfer from the tenth strip
Answer:
s = 23.72 m
v = 21.56 m/s²
Explanation:
given
time to reach the ground (t) = 2.2 second
we know that
a) s = u t + 0.5 g t²
u = 0 m/s
g = 9.8 m/s²
s = 0 + 0.5 × 9.8 × 2.2²
s = 23.72 m
b) impact velocity
v = √(2gh)
v = √(2× 9.8 × 23.72)
v = √464.912
v = 21.56 m/s²
Explanation:
Sorry but I don't Understand question