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yaroslaw [1]
2 years ago
5

What is your initial speed if you accelerate at 5.8 m/s/s for 3.0 seconds and achieve a final speed of 45 m/s?

Physics
1 answer:
Natali5045456 [20]2 years ago
8 0

Answer:

27.6 m/s

Explanation:

hopefully it makes sense and is visible

:)

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Answer:

The answer is "512 J".

Explanation:

bullet mass m_1 = 10 g= 10^{-2} \ kg\\\\

initial speed u_1 = 2\ \frac{Km}{s}= 2000\ \frac{m}{s}\\\\

block mass m_2 = 4\ Kg

initial speed v_2 =-4.2 \frac{m}{s}

final speed v_2= 0

Let v_1 will be the bullet speed after collision:

throughout the consevation the linear moemuntum

\to M_1V_1+m_2v_2=M_1U_1+m_2u_2\\\\\to (10^{-2} kg) V_1 +0 = (10^{-2} kg)(2000 \frac{m}{s}) + (4 \ kg)(-4.2 \frac{m}{s}) \\\\\ \to 10^{-2} v_1 = 20 -16.8\\\\

                = 320 \frac{m}{s}

The kinetic energy of the bullet in its emerges from the block

k=\frac{1}{2} m_1 v_1^2

   =\frac{1}{2} \times 10^{-2} \times 320\\\\=512 \ J

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3 years ago
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Answer:

The square of the hypotenuse is equal to the sum of the squares of the other two lengths.

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