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Tanzania [10]
3 years ago
7

A magnetic compass is placed near an insulated copper wire. When the wire is connected to a battery and a current is created, th

e compass needle moves and changes its position. Which is the best explanation for the production of a force that causes the needle to move?
(1)The copper wire magnetizes the compass needle and exerts the force on the compass needle.
(2)The compass needle magnetizes the copper wire and exerts the force on the compass needle.
(3)The insulation on the wire becomes charged, which exerts the force on the compass needle.
(4)The current in the wire produces a magnetic field that exerts the force on the compass needle.
Physics
2 answers:
olga nikolaevna [1]3 years ago
5 0

acts at a distance. fjghfrhgdfuighuidfgui

Luba_88 [7]3 years ago
4 0
4

Every current through a wire produced a magnetic field. And since the magnetic field of Earth is weak, it will get attracted towards the wire.
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A mass spectrometer applies a voltage of 2.00 kV to accelerate a singly charged positive ion. A magnetic field of B = 0.400 T th
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The mass of the ion is 5.96 X 10⁻²⁵ kg

<u>Explanation:</u>

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3 0
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AVprozaik [17]

Answer:

103239.89 days

Explanation:

Kepler's third law states that the square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.

                               a³ / T² = 7.496 × 10⁻⁶  (a.u.³/days²)

where,

a is the distance of the semi-major axis in a.u

T is the orbit time in days

Converting the mean distance of the new planet to astronomical unit (a.u.)

                       1 a.u = 9.296 × 10⁷ miles        

                                      \frac{4004 * 10^{6}}{9.296 * 10^{7}}  =  43.07\ a.u.

Substituting the values into Kepler's third law equation;

                                    \frac{(43.07)^{3}}{T^{2}}  =  7.496 * 10^{-6}  

                                    T^{2} = \frac{(43.07)^{3}}{7.496 * 10^{-6}} (days)²

                                    T^{2} = \sqrt{\frac{(43.07)^{3}}{7.496 * 10^{-6}}}

                                    T = 103239.89 days

An estimate time T for the new planet to travel around the sun in an orbit is 103239.89 days

7 0
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