Answer:
224.6 N
Explanation:
We can use first the formula to calculate the centripetal acceleration, given by:
where the Vt is the tangential velocity, and R is the radius of the circular motion.
Then, for our case we have:
And now we multiply this acceleration by Miguel's mass (11 kg) to obtain the centripetal force acting on him:
Answer:
<em>The correct choice is D. Its gravitational potential energy must increase</em>
Explanation:
<u>Conservation of Mechanical Energy</u>
The total amount of mechanical energy, in a closed system in the absence of dissipative forces like friction or air resistance, remains constant.
This means that energy cannot disappear or appear and that potential energy can become kinetic energy or vice versa.
In a closed system like a pendulum, two types of energies are considered: Gravitational potential (U) and kinetic (K). Thus, the sum of both energies must remain constant in time.
Suppose the pendulum is at a state where U=150 J, and K=350 J. The total mechanical energy is:
M = 150 J + 350 J = 500 J
If the kinetic energy decreases to a new value, say K = 200 J, then the gravitational potential must increase to compensate for this new condition, that is: U = 300 J
The correct choice is D. Its gravitational potential energy must increase
Answer:
0.137m²
Explanation:
Pressure = Force/Area
Given
Force = 41,500N
Pressure = 3.00atm
since 1atm = 101325.00 N/m²
3atm = 3(101325.00)
3atm = 303,975N/m²
Pressure = 303,975N/m²
Get the area
Area = Force/Pressure
Area = 41500/303,975
Area = 0.137m²'
Hence the surface area of the inside of the tire is 0.137m²
Answer:
the moment of inertia of the merry go round is 38.04 kg.m²
Explanation:
We are given;
Initial angular velocity; ω_1 = 37 rpm
Final angular velocity; ω_2 = 19 rpm
mass of child; m = 15.5 kg
distance from the centre; r = 1.55 m
Now, let the moment of inertia of the merry go round be I.
Using the principle of conservation of angular momentum, we have;
I_1 = I_2
Thus,
Iω_1 = I'ω_2
where I' is the moment of inertia of the merry go round and child which is given as I' = mr²
Thus,
I x 37 = ( I + mr²)19
37I = ( I + (15.5 x 1.55²))19
37I = 19I + 684.7125
37I - 19 I = 684.7125
18I = 684.7125
I = 684.7125/18
I = 38.04 kg.m²
Thus, the moment of inertia of the merry go round is 38.04 kg.m²
Answer: Period
Explanation: Properties of elements within a period on the periodic table change in a predictable way from one side of the table to the other. A period in the periodic table is a horizontal row. All elements in a row have the same number of electron shells.
