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Tanzania [10]
3 years ago
7

A magnetic compass is placed near an insulated copper wire. When the wire is connected to a battery and a current is created, th

e compass needle moves and changes its position. Which is the best explanation for the production of a force that causes the needle to move?
(1)The copper wire magnetizes the compass needle and exerts the force on the compass needle.
(2)The compass needle magnetizes the copper wire and exerts the force on the compass needle.
(3)The insulation on the wire becomes charged, which exerts the force on the compass needle.
(4)The current in the wire produces a magnetic field that exerts the force on the compass needle.
Physics
2 answers:
olga nikolaevna [1]3 years ago
5 0

acts at a distance. fjghfrhgdfuighuidfgui

Luba_88 [7]3 years ago
4 0
4

Every current through a wire produced a magnetic field. And since the magnetic field of Earth is weak, it will get attracted towards the wire.
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How many atoms are in a molecule of C6H12O6?
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The answer is 24

Explanation:

Its made up of 6 carbon atoms

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A vw bug is driving north on a straight two lane road at a constant 54 mph and chevy impala south at 47 on the same road (but di
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Velocity of vw bug is given as

v_1 = 54 mpH towards north

velocity of imphala is given as

v_2 = 47 mph towards south

now we need to find velocity of imphala relative to bug

v_{21} = v_2 - v_1

v_{21} = 47 - (-54) = 101 mpH

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Why is the perfect mechine is not possible in the real life?​
Vinvika [58]

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3 0
3 years ago
Two transverse waves travel along the same taut string. Wave 1 is described by y1(x, t) = A sin(kx - ωt), while wave 2 is descri
Vadim26 [7]

Answer:

6) Wave 1 travels in the positive x-direction, while wave 2 travels in the negative x-direction.

Explanation:

What matters is the part kx \pm \omega t, the other parts of the equation don't affect time and space variations. We know that when the sign is - the wave propagates to the positive direction while when the sign is + the wave propagates to the negative direction, but <em>here is an explanation</em> of this:

For both cases, + and -, after a certain time \delta t (\delta t >0), the displacement <em>y</em> of the wave will be determined by the kx\pm\omega (t+\delta t) term. For simplicity, if we imagine we are looking at the origin (x=0), this will be simply \pm \omega (t+\delta t).

To know which side, right or left of the origin, would go through the origin after a time \delta t (and thus know the direction of propagation) we have to see how we can achieve that same displacement <em>y</em> not by a time variation but by a space variation \delta x (we would be looking where in space is what we would have in the future in time). The term would be then k(x+\delta x)\pm\omega t, which at the origin is k \delta x \pm \omega t. This would mean that, when the original equation has kx+\omega t, we must have that \delta x>0 for k\delta x+\omega t to be equal to kx+\omega\delta t, and when the original equation has kx-\omega t, we must have that \delta x for k\delta x-\omega t to be equal to kx-\omega \delta t

<em>Note that their values don't matter, although they are a very small variation (we have to be careful since all this is inside a sin function), what matters is if they are positive or negative and as such what is possible or not .</em>

<em />

In conclusion, when kx+\omega t, the part of the wave on the positive side (\delta x>0) is the one that will go through the origin, so the wave is going in the negative direction, and viceversa.

4 0
3 years ago
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