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3 years ago

Death Star has a diameter of 160,000m and a mass of 5.1e17kg. Millennium Falcon has a mass of 1.36e6kg (data from Wookieepedia)

Physics

1 answer:

lions [1.4K]3 years ago

5 0

Answer:

7229 N

Explanation:

The gravitational force between the Death Star and the Millenium Falcon is given by:

$F=G\frac{mM}{R^2}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2}$ is the gravitational constant

$M=5.1\cdot 10^{17} kg$ is the mass of the Death Star

$m=1.36\cdot 10^6 kg$ is the mass of the Millennium Falcon

$R=\frac{160,000 m}{2}=80,000 m$ is the radius of the Death Star

Substituting numbers into the equation, we find the force

$F=(6.67\cdot 10^{-11})\frac{(1.36\cdot 10^6 kg)(5.1\cdot 10^{17} kg)}{(80,000 m)^2}=7229 N$

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ser-zykov [4K]

Answer:

-0.038 N

Explanation:

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3 years ago

For any molecule, formula unit, or ion, the sum of the average atomic masses of all the atoms represented in a formula is the.

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1 year ago

A 2.0 µF capacitor is charged through a 50,000 ohm resistor. How long does it take for the capacitor to reach 90% of full charge

Nesterboy [21]

Answer:

0.23 s

Explanation:

First of all, let's find the time constant of the circuit:

$\tau=RC$

where

$R=50,000 \Omega$ is the resistance

$C=2.0\mu F=2.0\cdot 10^{-6}F$ is the capacitance

Substituting,

$\tau=(50,000 \Omega)(2.0\cdot 10^{-6}F)=0.1 s$

The charge on a charging capacitor is given by

$Q(t)=Q_0 (1-e^{-t/\tau} )$ (1)

where

$Q_0$ is the full charge

we want to find the time t at which the capacitor reaches 90% of the full charge, so the time t at which

$Q(t)=0.90 Q_0$

Substituting this into eq.(1) we find

$0.90 Q_0 = Q_0 (1-e^{-t/\tau})\\0.90=1-e^{-t/\tau}\\e^{-t/\tau}=1-0.90=0.10\\-\frac{t}{\tau}=ln(0.10)\\t=-\tau ln(0.10)=(0.1 s)ln(0.10)=0.23 s$

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3 years ago

A plane starting from rest accelerates at 3m/s2 for 25s. Calculate the increase in velocity after:

horsena [70]

Initial velocity=u=0m/s
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Time not needed now

Case-1:-

Time=1s
Final velocity=v

$\\ \rm\hookrightarrow v=u+at$

$\\ \rm\hookrightarrow v=0+3(1)$

$\\ \rm\hookrightarrow v=3m/s$

Case-2:-

Time=3s

$\\ \rm\hookrightarrow v=0+3(3)$

$\\ \rm\hookrightarrow v=9m/s$

Case-3:-

Time=25s

$\\ \rm\hookrightarrow v=0+3(25)$

$\\ \rm\hookrightarrow v=75m/s$

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2 years ago

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3 years ago

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