Answer:
1. Energy = 2880 Joules.
2. Energy = 60 Joules.
3. Quantity of charge = 120 Coulombs.
Explanation:
Given the following data;
1. Voltage = 12 Volts
Current = 0.5 Amps
Time, t = 8 mins to seconds = 8 * 60 = 480 seconds
To find the energy;
Power = current * voltage
Power = 12 * 0.5
Power = 6 Watts
Next, we find the energy transferred;
Energy = power * time
Energy = 6 * 480
Energy = 2880 Joules
2. Charge, Q = 4 coulombs
Potential difference, p.d = 15V
To find the total energy transferred;
Energy = Q * p.d
Energy = 4 * 15
Energy = 60 Joules
3. Voltage = 6 Volts
Current = 1 Amps
Time = 2 minutes to seconds = 2 * 60 = 120 seconds
To find the quantity of charge;
Quantity of charge = current * time
Quantity of charge = 1 * 120
Quantity of charge = 120 Coulombs
Scientific Method: Because, they use their method which the scientific one to solve investigations.
Answer:
a=F/m
a=12N/3kg (here newton can be written as kgm/s^2 so kg will be cancelled)
a=4m/s^2
Explanation:
<span>Freezing involves the decrease in value of latent heat by 80 Cal/gm and a change of state from the Liquid phase to the solid phase.
So, in short, Fill in the blank as follows:
1st blank = Release/decrease
2nd blank = Liquid
Hope this helps!
</span>
Answer:
600 and 1500 [ohm
Explanation:
To solve this problem we must use ohm's law, which tells us that the voltage is the product of the current by the resistance, so we have:
V = I*R
where:
V = voltage [V]
I = current [amp]
R = resistance [ohm]
<u>Therefore:</u>
R = V/I
R1 = 60/(40*10^-3) = 1500 [ohm]
R2 = 60/(100*10^-3) = 600 [ohm]
So the resistance should be among 600 and 1500 [ohm]
