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3 years ago

Which of the following is a chemical change?

Physics

2 answers:

svet-max [94.6K]3 years ago

5 0

The answer is D. Water breaking down into hydrogen and oxygen

HTH ^^

slamgirl [31]3 years ago

4 0

D water breaking down into hydrogen and oxygen

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A boat travels at 30 mph for a huge, solid cliff that is about 3,000 meters away. When the horn on the boat makes a toot, you ca

AleksandrR [38]

Answer:The frequency of the echo is slightly decreased

Explanation:

Given

speed of boat $=30\ mph$

cliff is $3000\ m$ away

when boat is still , suppose t is the time taken by the echo to reach observer on the boat

But as soon as boat starts moving the distance between cliff and boat decreasing and time for echo to reach observer also decreases

and we know $time \propto \frac{1}{frequency}$

therefore frequency of the echo slightly decreased.

5 0

3 years ago

At positions and_______, _______kinetic energy is maximum. At position

worty [1.4K]

Hi there!

I believe it looks like this.

At positions A, G kinetic energy is maximum.
At position D, potential energy is maximum.

Hope this helps! ☺♥

7 0

3 years ago

Read 2 more answers

A square-based shipping crate is being designed that must contain a volume of 16 ft3 . The material that is used for the base an

Vlada [557]

Answer:

Explanation:

Given

volume $V=16 ft^3$

Suppose base is square with side L

height of crate is h

Volume $V=L^2\times h$

$16=L^2\times h$

Cost of top and bottom area $c_1=3L^2$

Cost of Side area $c_2=4Lh\times 2=8Lh=8L\times \frac{16}{L^2}=\frac{128}{L}$

Total Cost $C=c_1+c_2$

Total Cost $C=3L^2+\frac{128}{L}$

Differentiate C w.r.t Length

$\frac{dC}{dL}=6L-\frac{128}{L^2}$

$L^3=\frac{128}{6}$

$L=2.75 ft$

$h=\frac{16}{2.75^2}=11.46 ft$

Dimensions are $L\times L\times h=2.75\times 2.75\times 11.46$

6 0

2 years ago

All nuclear reactions generate radioactive waste. Which answer correctly lists

sasho [114]

The answer would be A because

4 0

2 years ago

Use the general formulas for gravitational force and centripetal force to derive the relationship between speed (v) and orbital

german

Solution :

We know that :

Formula for Gravitational force is given by :

$F_g=\frac{Gmn}{r^2}$

where, G is the gravitational constant

M is the mass of the bigger body

m is the mass of the smaller body

r is the distance between the two bodies.

And the formula for the centripetal force is given by :

$F_c=\frac{mv^2}{r}$

where, m is the mass of the rotating body

v is the velocity

r is the radius of rotation of the body.

We know that mathematically, the gravitational force is equal to the centripetal force of the body.

Therefore,

$F_g=F_c$

$\frac{GMm}{r^2}=\frac{mv^2}{r}$

$\sqrt{\frac{GM}{r}}=v$

Hence derived.

5 0

3 years ago