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2 years ago

Factor completely 4а^2 - 8а - 5

Mathematics

1 answer:

Evgesh-ka [11]2 years ago

5 0

Answer:

(2a + 1)(2a - 5)

Step-by-step explanation:

Given

4a² - 8a - 5

Consider the factors of the product of the coefficient of the a² term and the constant term which sum to give the coefficient of the a- term

product = 4 × - 5 = - 20 and sum = - 8

The factors are + 2 and - 10

Use these factors to split the a- term

4a² + 2a - 10a - 5 ( factor the first/second and third/fourth terms )

= 2a(2a + 1) - 5(2a + 1) ← factor out (2a + 1) from each term

= (2a + 1)(2a - 5)

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Answer:

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Step-by-step explanation:

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2 years ago

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Answer:

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2 years ago

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2 years ago

Solve with steps<br> 5^(x+3)=25^(x-2)

Taya2010 [7]

5^(x+3)=25^(x-2)

Apply the exponent rule ( 5 ^2 = 25, so remove the 5 and replace 25?with 2)

x + 3 = 2(x-2)

Simplify:

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Add 4 to both sides:

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Subtract x from both sides

X = 7

Answer: x = 7

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2 years ago