Answer:
After 1.5 second of throwing the ball will reach a maximum height of 44 ft.
Step-by-step explanation:
The height in feet of a ball after t seconds of throwing is given by the function
h = - 16t² + 48t + 8 .......... (1)
Now, condition for maximum height is
{Differentiating equation (1) with respect to t}
⇒
seconds.
Now, from equation (1) we get
h(max) = - 16(1.5)² + 48(1.5) + 8 = 44 ft.
Therefore, after 1.5 seconds of throwing the ball will reach a maximum height of 44 ft. (Answer)
Answer:
For number 3 its C (sorry im doing the same thing and im stuck on the last ones)
Step-by-step explanation:
Ok so:
4(4x+3) = 19x + 9 - 3x +3
parenthesis first:
4 x 4x = 16x then 4 x 3 = 12
16x + 12 = 19x + 9 - 3x + 3
combine :) :
19x - 3x = 16x then 9 + 3 = 12
16x + 12 = 16x +12
-12 -12
16x = 16x
They are the same equations lol they equal 0.
2,000
hope I could help you out :]