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sveticcg [70]
4 years ago
15

The motion map shows an object’s position and velocity at given times. A long black arrow right labeled x. Above that are 5 gree

n arrows pointing right end to end and are the same length. There are two more green arrows each a little shorter. Farther up from the line is a point. Much farther above that are 3 green arrows each longer than the previous. How can the map be changed so it shows constant acceleration after the object changes direction? by adding vectors that are all the same length and placing them above the current top row of vectors by adding vectors that gradually increase in length and placing them above the current top row of vectors by adding vectors that are all the same length and placing them below the current bottom row of vectors by adding vectors that gradually increase in length and placing them below the current bottom row of vectors

Physics
2 answers:
MissTica4 years ago
9 0

The map be changed <u>by adding vectors that are all the same length and placing them above the current top row of vectors</u>

<h3>Further explanation</h3>

A motion map represents the position, velocity, or acceleration of an object at various time readings

a small point or dot describes the position of the object. the object's velocity / acceleration is represented by an arrow / vector.

In this motion map, The arrows (vectors) are all the same length (same speed) and point in the same direction (direction to the right) for t = 0 (origin) to t = 4s

At t = 5s, the object has slowed down, and at t = 7s and 8s the object stops

At t = 9s-11 s, the object accelerates to the left

So the position of the next moving object will be above the previous movement, and the length of the same vector shows the same speed / acceleration

So that motion maps show constant acceleration after the object changes direction, it can be done by adding vectors that are all the same length and placing them above the current top row of vectors

<h3>Learn more</h3>

The initial velocity of the bird before the gust of wind

brainly.com/question/13207873

Keywords: motion map,  constant acceleration, dot, arrows, object,length, vectors, row

#LearnwithBrainly

leonid [27]4 years ago
4 0

Answer:

The object starts away from the origin and then moves toward the origin at a constant velocity. Next, it stops for one second. Finally, it moves away from the origin at a greater constant velocity.v

Explanation:

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8 0
4 years ago
You and a friend are playing with a bowling ball to demonstrate some ideas of Rotational Physics. First, though, you want to cal
RideAnS [48]

Answer:

K_{total} = 19.4 J

Explanation:

The total kinetic energy that is formed by the linear part and the rotational part is requested

         K_{total} = K_{traslation}  + K_{rotation}

let's look for each energy

linear

        K_{traslation} = ½ m v²

rotation

        K_{rotation} = ½ I w²

the moment of inertia of a solid sphere is

       I = 2/5 m r²

we substitute

       K_{total} = ½ mv² + ½ I w²

           

angular and linear velocity are related

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we substitute

           K_{total} = ½ m w² r² + ½ (2/5 m r²) w²

           K_{total} = m w² r² (½ + 1/5)

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let's calculate

           K_{total} = \frac{7}{10}   6.40 16.0² 0.130²

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6 0
3 years ago
A worker is pushing a crate of tools up a ramp into a truck. The crate has a mass of 120 kg and is accelerating at a rate of 1.0
jolli1 [7]

Answer:

B) 0.493

Explanation:

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8 0
3 years ago
Read 2 more answers
A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.2 m/s. The car is a distanc
dem82 [27]

Explanation:

It is known that the relation between speed and distance is as follows.

               velocity = \frac{distance}{time}

As it is given that velocity is 6 m/s and distance traveled by the bear is (d + 29). Therefore, time taken by the bear is calculated as follows.

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As the tourist is running in a car at a velocity of 4.2 m/s. Hence, time taken by the tourist is as follows.

              t_{tourist} = \frac{d}{4.2} ............. (2)

Now, equation both equations (1) and (2) equal to each other we will calculate the value of d as follows.

              t_{bear} = t_{tourist}

       \frac{(d + 29)}{6 m/s} = \frac{d}{4.2}

                   4.2d + 121.8 = 6d

                         d = \frac{121.8}{1.8}

                            = 67.66

Thus, we can conclude that the maximum possible value for d is 67.66.

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