Answer:
43°
Explanation:
Sin tita m= mlambda/d
Sin 20°= lambda/d
Sin tita 2= 2(lambda/d)
Sin tita 2= 2 sin 20
Sin tita 2= 0. 684
Tita 2= sin-1(0. 684)
Tita 2= 43°
Thus, the angle of the second order maximum is 43°
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