Answer:
ω = 5.41 rad/s
Explanation:
Since the rod is rotating around its axis, angular momentum will play part in this question.
The conservation of angular momentum implies that
So, the initial angular momentum is
The final angular momentum includes the rod and the bullet together. So,
Hello!
Since the two weights are <em>off</em> the table, the block will move towards letter F.
I hope this helps :))
When a mirror is rotated . . .
-- The incident ray doesn't turn. It's just the line from the source to the mirror.
It would be there, in the same place, even if there was no mirror.
-- The normal turns. It's the line perpendicular to the mirror, so it must turn
with the mirror.
-- Since the normal tuns and the incident ray doesn't, the angle between them
must change. And since the angle of the reflected ray is equal to the angle of
the incident ray, the reflected ray must also turn.
