The molecular formula of a compound is C₂H₂O₄.
Take 100 grams of compound:
1) ω(C) = 26.7% ÷ 100% = 0.267
m(C) = ω(C) × m(compound)
m(C) = 0.267 × 100 g.
m(C) = 26.7 g.
n(C) = m(C) ÷ M(C).
n(C) = 26.7 g ÷ 12 g/mol.
n(C) = 2.22 mol; amount of carbon
2) ω(H) = 2.2 % ÷ 100% = 0.022
m(H) = 0.022 × 100 g.
m(H) = 2.2 g.
n(H) = 2.2 g ÷ 1 g/mol.
n(H) = 2.2 mol; amount of hydrogen
3) ω(O) = 71.1 % ÷ 100%.
ω(O) = 0.711
m(O) = 0.711 × 100 g
m(O) = 71.1 g
n(O) = 71.1 g ÷ 16 g/mol
n(O) = 4.4 mol; amount of oxygen
4) n(C) : n(H) : n(O) = 2.2 mol : 2.2 mol : 4.4 mol /2.2 mol.
n(C) : n(H) : n(O) = 1 : 1 : 2
M(CHO₂) = 45 amu; empirical formula
90 amu ÷ 45 amu = 2 CHO₂
More info about empirical formula: brainly.com/question/1873039
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The answer is true . hope this helps!
The formula of aspartame is <span>C14H18N2O5.
From the periodic table:
molecular mass of hydrogen = 1 grams
molecular mass of carbon = 12 grams
molecular mass of nitrogen = 14 grams
molecular mass of oxygen = 16 grams
This means that:
molar mass of aspartame = 14(12)+18(1)+2(14)+5(16) = 294 grams
Therefore, each 294 grams of aspartame contains 5(16) = 80 grams of oxygen. To know number of grams of oxygen in 23.6 grams of aspartame, simply use cross multiplication as follows:
mass of oxygen = (23.6x80) / 294 = 6.42 grams</span>
Hv= heat of vapourization of water= 2260J/g
heat=2260*35
=79100 J
