Answer:
23.086 mile/h
Explanation:
Given,
Distance Tyson Gay run = 100 m
time of run, t = 9.69 s
average speed of the in mph = ?
Speed of the Gay =
v = 10.32 m/s
1 m = 3.281 ft
10.32 m = 33.86 ft
1 mile = 5280 ft
1 ft = 1.8939 x 10⁻⁴ mile
33.86 ft/s = 6.413 x 10⁻³ miles/s
Speed of Tyson in mile/hr = 6.413 x 10⁻³ x 3600
= 23.086 mile/h
Hence, speed of Tyson Gay's in mile/ hr is equal to 23.086 mph.
Explanation:
It is given that,
= -40 mi/h,
= -40 mi/h
The negative sign indicates that x and y are decreasing.
We have to find . Equation for the given variables according to the Pythagoras theorem is as follows.
Now, we will differentiate each side w.r.t 't' as follows.
or,
So, when x = 4 mi, and y = 3 mi then z = 5 mi.
As,
=
=
= 52
Thus, we can conclude that the cars are approaching at a rate of 52 mi/h.