What is the term for the matter through which a mechanical wave travels?

The law of conservation of momentum states that...

Brums [2.3K]

Answer:

The momentum before is equal to the momentum after

Explanation:

It is equal and should level out in an equation.

4 0

3 years ago

An Argon laser (λ = 5.0×102nm) shines down a silica glass fiber-optic cable with index of refraction 1.46. What is the speed of

Yanka [14]

Answer:

The speed of the laser light in the cable, $c_f=2.1\times 10^8\ m/s$

Explanation:

It is given that,

Wavelength of Argon laser, $\lambda=5\times 10^2\ nm=5\times 10^{-7}\ m$

Refractive index, n = 1.46

Let $c_f$ is the speed of the laser light in the cable. The speed of light in a medium is given by :

$c_f=\dfrac{c}{n}$

$c_f=\dfrac{3\times 10^8\ m/s}{1.46}$

$c_f=2.05\times 10^8\ m/s$

or

$c_f=2.1\times 10^8\ m/s$

So, the speed of the laser light is $2.1\times 10^8\ m/s$ . Hence, this is the required solution.

4 0

3 years ago

Read 2 more answers

A horizontal uniform board of weight 125N and length 4 m is supported by vertical chains at each end. A person weighing 500N sit

Misha Larkins [42]

Let's apply an equation of equilibrium to the situation: The sum of the moments about the left end of the board must equal 0.

We have three moments to add. Positive force values indicate upward direction and negative values indicate downward direction. All distances given below are measured to the right side of the left end of the board:

The weight of the board, -125N, located at 2m (center of the board due to its uniform density)
The tension in the right chain, +250N, located at 4m
The weight of the person, -500N, located at a distance "x"

The sum of the moments must equal 0 and is given by:

ΣFx = 0

F is the magnitude of force, x = distance from the left end of the board

Plug in all of the force and distance values and solve for x:

ΣFx = 250(4) - 125(2) - 500x = 0

500x = 750

x = 1.5m

7 0

3 years ago

At what velocity would a 5.0 kg dog have to run to have the same

Natali5045456 [20]

Answer:

The velocity with which the 5.0 kg dog has to run to have the same momentum as the 30 kg pig walking at 3.0 m/s is 18 m/s

Explanation:

Given that the mass of the dog = 5.0 kg

The mass of the pig = 30 kg

The speed with which the pig is walking = 3.0 m/s

We have that linear momentum = Mass × Velocity

Therefore, the momentum of the pig, m₁ = 30 kg × 3.0 m/s = 90 kg·m/s

m₁ = 90 kg·m/s

The momentum of the dog m₂ = Mass of the dog × Velocity of the dog

Given that m₁ is to be equal to m₂, we have;

m₁ = 90 kg·m/s = m₂ = Mass of the dog × Velocity of the dog

90 kg·m/s = m₂ = 5.0 kg × Velocity of the dog

m₂ = 5.0 kg × Velocity of the dog = 90 kg·m/s

5.0 kg × Velocity of the dog = 90 kg·m/s

Velocity of the dog = 90 kg·m/s/(5.0 kg) = 18 m/s

The velocity with which the 5.0 kg dog has to run to have the same momentum as the 30 kg pig walking at 3.0 m/s = 18 m/s.

4 0

3 years ago

A flexible loop has a radius of 10.5 cm and it is in a magnetic field of B = 0.117 T. The loop is grasped at points A and B and

MAXImum [283]

Explanation:

Given that,

Radius = 10.5 cm

Magnetic field = 0.117 T

Time = 0.243 s

After stretched, area is zero

(I). We need to calculate the magnetic flux through the loop before stretched

Using formula of magnetic flux

$\phi=B\times A$

$\phi=B\times \pi r^2$

Where, B = magnetic field

r = radius

Put the value into the formula

$\phi=0.117\times3.14\times(10.5\times10^{-2})^2$

$\phi=4.05\times10^{-3}\ Tm^2$

(II). We need to calculate the magnetic flux through the loop after stretched

$\phi=B\times A$

Here, A = 0

$\phi=0$

So, The magnetic flux through the loop after stretched is zero.

(III). We need to calculate the magnitude of the average induced electromotive force

Using formula of the induced electromotive force

$\epsilon=-\dfrac{d\phi}{dt}$

$\epsilon=-\dfrac{\phi_{after}-\phi_{before}}{t}$

$\epsilon=-\dfrac{0-4.05\times10^{-3}}{0.243}$

$\epsilon =16.67\times10^{-3}\ V$

Hence, This is the required solution.

3 0

3 years ago