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chubhunter [2.5K]

3 years ago

13

A race car is moving with a velocity of 144 kilometers/hour. The driver applies the brakes, and the car comes to a halt in 12.0

seconds. What is the average acceleration of the car during those 12.0 seconds?

1 answer:

anzhelika [568]3 years ago

8 0

-12 k/s/s (the number is right the abbreviation might not be)

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Can someone help me figure out how to find tension in a rope? The question is:

Simora [160]

You are welcome.......

8 0

3 years ago

A 4.00 kg ball is swung in a circle on the edge of a 1.50 m rope. The time it takes for the ball to complete one rotation is 3.4

lorasvet [3.4K]

Answer:

The answer is below

Explanation:

The length of the rope is equal to the radius of the circle formed by the complete rotation of the rope. Therefore the radius = 1.50 m.

a) The distance covered by the rope when completing one rotation is the same as the perimeter of the circle. Hence:

Distance covered in one rotation = 2π * radius = 2π * 1.5 = 3π meters

The velocity of the ball = Distance / time = 3π meters / 3.4 seconds = 2.77 m/s

b) The initial velocity (u) is 0 m/s, the final velocity is 2.77 m/s during time (t) = 3.4 s. Hence acceleration (a):

v = u + at

2.77 = 3.4a

a = 0.82 m/s²

c) Force on ball = mass * acceleration = 4 * 0.82 = 3.28 N

8 0

2 years ago

Liquids take the shape of the bottom of their container, while gases take the shape of their entire container. The shape solids

motikmotik

Answer:

...

Explanation:

sigh its not that hard

Any liquid takes form of the shape of the container it goes into.

Gasses take the form of the whole thing because it spreads throughout it.

Solids are already a shape so it cant take the shape of the container if it already has one. yk

4 0

2 years ago

An airplane is heading due south at a speed of 560 km/h . If a wind begins blowing from the southwest at a speed of 80.0 km/h (a

polet [3.4K]

Answer:

the magnitude of Vpg = 493.711 km/h

Explanation:

given data

speed Vpg = 560 km/h

speed Vwg = 80 km/h

solution

we get here magnitude of the plane velocity w.r.t. ground is

we know that the Vpg = Vpw + Vwg .....................1

writing the component of the velocity that is

Vpw = (0 km/h î - 560 km/h j )

Vwg = (80 cos 45 km/h î + 80 sin 45 km/h j)

adding these

Vpg = (0+80 cos 45 km/h ) î + ( -560 + 80 sin 45 km/h j)i

Vpg = (42.025 ) î (-491.92 km/h)j

now we take magnitude

the magnitude of Vpg = $\sqrt{(42.025^2+(-491.92)^2)} km/h$

the magnitude of Vpg = 493.711 km/h

5 0

2 years ago

g An object with mass m=2 kg is completely submerged, and tethered, to the bottom of a large body of water. If the density of th

Anit [1.1K]

Answer:

The tension in the rope is 20 N

Solution:

As per the question:

Mass of the object, M = 2 kg

Density of water, $\rho_{w} = 1000\ kg/m^{3}$

Density of the object, $\rho_{ob} = 500\kg/m^{3}$

Acceleration due to gravity, g = $10\ m/s^{2}$

Now,

From the fig.1:

'N' represents the Bouyant force and T represents tension in the rope.

Suppose, the volume of the block be V:

V = $\frac{M}{\rho_{ob}}$ (1)

Also, we know that Bouyant force is given by:

$N = \rho_{w}Vg$

Using eqn (1):

$N = \rho_{w}\frac{M}{\rho_{ob}}g$

$N = 1000\frac{2}{500}\times 10 = 40\ N$

From the fig.1:

N = Mg + T

40 = 2(10) + T

T = 40 - 20 = 20 N

$N = \rho_{w}Vg$

3 0

2 years ago