How many different bases of DNA

Chemistry

1 answer:

const2013 [10]3 years ago

4 0

Answer:

four

Explanation:

adenine, thymine, guanine, and cytosine

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Consider the following reversible reaction.

andriy [413]

Answer:

No one is correct. The correct expression is:

Keq = [H₂]² . [O₂]² / [H₂O]²

Explanation:

To build the Keq expression in a chemical equilibrium you must consider the molar concentrations of reactants / products, and they must be elevated to the stoichiometric coefficient.

The balance reaction is:

2 H₂O (g) ⇄ 2 H₂ (g) + O₂ (g)

Keq = [H₂]² . [O₂] / [H₂O]²

In opposite side: 2 H₂ (g) + O₂ (g) ⇄ 2 H₂O (g)

Keq = [H₂O]² / [H₂]² . [O₂]

6 0

4 years ago

I need to find the chemical equation

Yuri [45]

Answer:

2NaCN + CaCO3 --> Na2CO3 + Ca(CN)2

Explanation:

Knowing the names gets us: NaCN + CaCO3 --> Na2CO3 + Ca(CN)2

Balance: there are two sodiums and cyanides on the product side so add a 2 to the reactant side.

4 0

3 years ago

Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e

notsponge [240]

Answer: The concentration of $Sn^{2+}$ in the cell is $9.0\times 10^{-3}M$

Explanation:

We are given:

Oxidation half reaction: $Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-$ $E^o_{Zn^{2+}/Zn}=-0.76V$

Reduction half reaction: $Sn^{2+}(aq.)+2e^-\rightarrow Sn(s)$ $E^o_{Sn^{2+}/Sn}=-0.136V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.